CODEWITHSUNDEEP
bashfind
rerboi
rerboi

Reputation: 93

copy directory structure without files

Hello i am trying to make a script which takes two arguments (names of directories) and copies the structure of the first into the other.

This is my code:

cd $1 && find . -type d -exec mkdir -p /$2/{} \;

when i run the script i dont get any errors but nothing happens. What am i doing wrong please help thank you.

edit: the script is saved in home and both directories are also in home (~). i run the script in terminal:

sudo bash DN1c.sh dir1 dir2

first directory has multiple subdirectories and the second directory is empty

Upvotes: 2

Views: 2403

Answers (2)

oguz ismail
oguz ismail

Reputation: 50750

export src=$1/. dest=$2
find "$src" -type d -exec bash -c 'printf "%s\0" "${@//"$src"/"$dest"}"' sh {} + | xargs -0 mkdir -p

Upvotes: 2

dawg
dawg

Reputation: 103814

You could use rsync to copy files and/or directories.

To copy directories only, set --max-size=0 and no files will be copied.

Example:

rsync -r -n -v --max-size=0 src_path/ dest_path

       ^                                        recursive
          ^                                     dry run - nothing copied
             ^                                  verbose
                     ^                          no files
                              ^                 src path
                                    ^           use a trailing / if you don't 
                                                want the src_path created
                                                at dest
                                           ^    dest path

Upvotes: 1

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