CODEWITHSUNDEEP
pythonmysqlsqlalchemy
Jay Patel
Jay Patel

Reputation: 47

Getting sum of two different tables columns to single column with group_by

First query for InvoiceOne table to group_by category and get sum of totalExGst:

sortCategory = db.session.query(
            InvoiceOne.category, db.func.sum(
                InvoiceOne.totalExGst).label('Total')
        ).filter(and_(InvoiceOne.storeNumber == '98376', InvoiceOne.weekEndDate == '2020-03-22')).group_by(InvoiceOne.category)

Second query does same thing with BankData table:

sortCategory = db.session.query(
            BankData.category, db.func.sum(
                BankData.debit).label('Total_BankData')
        ).filter(and_(BankData.storeNumber == '98376', BankData.weekEndDate == '2020-03-22')).group_by(BankData.category)

I would like to join this query together so instead of getting Total and Total_BankData

I can get only one column for total.

Upvotes: 0

Views: 102

Answers (1)

Taebow
Taebow

Reputation: 134

I suggest you go with subqueries :

sortCategory1 = db.session.query(
    InvoiceOne.category,
    db.func.sum(InvoiceOne.totalExGst).label('Total')
).filter(
    and_(
        InvoiceOne.storeNumber == '98376',
        InvoiceOne.weekEndDate == '2020-03-22')
).group_by(InvoiceOne.category).subquery()

sortCategory2 = db.session.query(
    BankData.category, 
    db.func.sum(BankData.debit).label('Total_BankData')
).filter(
    and_(
        BankData.storeNumber == '98376', 
        BankData.weekEndDate == '2020-03-22')
).group_by(BankData.category).subquery()


sortCategoryTotal = db.session.query(
    sortCategory1.c.category,
    sortCategory1.c.Total + sortCategory2.c.Total_BankData
).join(sortCategory2, sortCategory1.c.category == sortCategory2.c.category)

Upvotes: 1

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