CODEWITHSUNDEEP
for-looptkinteroptionmenu
Jamie Whalen
Jamie Whalen

Reputation: 11

Editing and Capturing new option from optionMenu Tkinter

I created a list of optionMenus via a for loop. I need to tie my optionMenu selection to the optionMenu it came from. The for loop, I think, is making it so I am unable to tie the two values together.

def get_selection(choice):
    popUp_list.append(choice)

if num >= 1 and num <5:
    for num in range(1,5):
        choice = StringVar(root2)
        choices = {'Application', 'File', 'Website'}
        choice.set('Choose Type')

        popUpMenu = OptionMenu(root2, choice, *choices, command = Controller.get_selection)
        popUpMenu.grid(row=num, column=0)

I know it would be easier to hard code the option menus, but for reasons I don't want to get in to, the for loop is necessary. Not for this part specifically, but for another part of my code. It's just easier to use this example here.

When an option is selected from the menus, I am able to pull the values and that works great. However, if a user makes a first selection and then wants to update their selection, I have no way to capture that. It creates a "new" selection, not tied to the optionMenu. So the new option does not replace the old option. It just creates a new selection.

Is there a way to pass the popUpMenu number through the Controller .get_selection function? When trying to pass another variable doing something on the lines of:

def get_selection(choice, num):
    popUp_list.append(choice)
    print(num)
popUpMenu = OptionMenu(root2, choice, *choices, command = lambda: Controller.get_selection(choice, num))

I get the error below and I'm not able to get the option selection. I'm not sure what to put as the first value. Inputting choice does not work.

self.__callback(self.__value, *args) TypeError: () takes 0 positional arguments but 1 was given

Upvotes: 1

Views: 53

Answers (1)

Jamie Whalen
Jamie Whalen

Reputation: 11

I was able to solve this. I updated my code to :

    if num >= 1 and num <5:
        for num in range(1,5):
            choice = StringVar(root2)
            choices = {'Application', 'File', 'Website'}
            choice.set('Choose Type')


            popUpMenu = OptionMenu(root2, choice, *choices, command = lambda choice = choice, num = num: (Controller.get_selection(choice, num)))

So, making your command statement like: command = lambda choice = choice, num = num: (Controller.get_selection(choice, num)))

allows you to pass variables into your function.

Upvotes: 0

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