Reputation: 33
The program should print all the input lines which length is longer than MINLINE
5 and shorter than MAXLINE
10. Ref. K&R book exercise 1.17
#include <stdio.h>
#define MAXLINE 10
#define MINLINE 5
int getlines(char lines[], int maxline);
int main()
{
int length;
char lines[MAXLINE];
while ((length = getlines(lines, MAXLINE)) > 0)
{
if (length > MINLINE)
printf("%s", lines);
}
return 0;
}
int getlines(char lines[], int maxline)
{
int i, c;
for (i = 0; i < maxline - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
{
lines[i] = c;
}
if (c == '\n')
{
lines[i] = c;
++i;
}
lines[i] = '\0';
return i;
}
Desired outpur should be like this :-
Hello\n
Hello\n
hi\n
excuseMe\n
excuseMe\n
longLineNotToBePrinted\n
done
done
but unexpectedly the program printing lines that are far longer than MAXLINE
and sometimes printing those omitting some trailing characters.
Upvotes: 0
Views: 125
Reputation: 33
/* Updated code. Now it is working fine. Problems were both in main() function and in the function getlines().
#include <stdio.h>
#define MAXLINE 10
#define MINLINE 5
int getlines(char lines[], int maxline);
main()
{
int length;
char lines[MAXLINE];
while ((length = getlines(lines, MAXLINE)) > 0)
{
if (length > MINLINE)
{
/* As the input line can be longer than MAXLINE and in that case there will be no '\n' escape sequence to be stored in the lines[MAXLINE] array so we have used the if block to flow the control in such a way that when the input line is longer than MAXLINE, the output string will be printed manually with a '\n' *newline character. */
if (length > MAXLINE)
printf("%s\n", lines);
else
printf("%s", lines);
}
}
return 0;
}
int getlines(char lines[], int maxline)
{
int i, j, c;
i = 0;
for (j = 0; (c = getchar()) != EOF && c != '\n'; ++j)
{
/* In the for loop this time we didn't use the condition 'j < maxline
-1' as getchar() needs to read the whole input line no matter it's length(can be greater than MAXLINE), rather we have used the 'j < maxline -1' condition as a nested if block inside the for loop. While doing this to keep the getchar() function busy reaching the last input character no matter how long the line is we have used two variable i and j to overcome the problem in such a way that i will be used to store characters in the lines[MAXLINE] array, while j will be increased untill it reaches the end of the line. */
if (j < maxline - 1)
{
i = j;
lines[i] = c;
++i;
}
}
if (c == '\n')
{
if (j < maxline - 1)
{
lines[i] = c;
++i;
++j;
}
else
++j;
}
lines[i] = '\0';
return j;
}
Upvotes: 0
Reputation: 311088
For starters this function
int getlines(char lines[], int maxline)
{
int i, c;
for (i = 0; i < maxline - 1 && (c = getchar()) != EOF && c != '\n'; ++i)
{
lines[i] = c;
}
if (c == '\n')
{
lines[i] = c;
++i;
}
lines[i] = '\0';
return i;
}
has undefined behavior because it can store the character '\0'
at position maxline
that is outside the array lines
that has the valid range of indices [0, maxline).
As for your question about the output then if you entered a text that is greater than maxline
then the function will return a string that does not contain the new line character '\n'
. So the next string will be outputted in the same line.
Upvotes: 1