CODEWITHSUNDEEP
c
user11333485
user11333485

Reputation:

Print the input one word per line

right now I am writing a program on C language based on the task 1.12 from Brian and Ritchie book. The program has to output the input stream one word per line. Here is the code:

#include <stdio.h>

int main(){
int ct;
while((ct = getchar()) != EOF){
    if(ct == ' '){
        ct = ct - ' ';
        putchar(ct);
        printf("\n");
    }else if(ct == '\n'){
        ct = ct - '\n';
        putchar(ct);
        printf("\n");
    }
  }
}

It seems to work, but it only outputs blank lines when I enter the input. Where did I mess up?

Upvotes: 0

Views: 199

Answers (1)

awarrier99
awarrier99

Reputation: 3855

In your code, you have the two cases where you check if ct is either a space (' ') or a newline character ('\n'), and these are the only places where you are printing out the character, using putchar. Your code isn't ever printing anything out outside of these two cases, so you need to add a case to handle regular characters and to print those out as well. Something like:

#include <stdio.h>

int main(){
int ct;
while((ct = getchar()) != EOF){
    if(ct == ' '){
        ct = ct - ' ';
        putchar(ct);
        printf("\n");
    }else if(ct == '\n'){
        ct = ct - '\n';
        putchar(ct);
        printf("\n");
    } else {
        putchar(ct)
  }
}

Also, while putchar does take an int as an argument, you do not need to manually convert it using ct - ' ', for example. You can pass the ct char directly to putchar and it will print it out accordingly

Upvotes: 1

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