CODEWITHSUNDEEP
javalinkedhashmap
sHIFT0O
sHIFT0O

Reputation: 41

LinkedHashMap get(key) return null even when the value is present

The task is to ask for a definitions of some random cards. After I introduce the cards and I access this method, the value corresponding to the key is present and it still returns null.

pair.get(a) always printing null

  public static void ask() {
        System.out.println("How many times to ask?");
        int ask = scan.nextInt();
        scan.nextLine();

        Random random = new Random();
        Object[] values = pair.keySet().toArray();
        int retur = random.nextInt(values.length);
        int i = 0;
        for (String iterator : pair.keySet()) {
            if (i <= ask) {
                System.out.println("Print the definition of \"" + values[retur] + "\":");
                String a = scan.nextLine();
                System.out.println(a.equals(pair.get(values[retur])) ? "Correct answer." :
                        "Wrong answer. The correct one is \"" + pair.get(values[retur]) +
                                "\", you've just written the definition of \"" + pair.get(a)  + "\".");
            }else
                break;
        }

Upvotes: 0

Views: 1602

Answers (1)

Matthew Formosa
Matthew Formosa

Reputation: 468

If I understand your code correctly the problem here is that you are trying to retrieve a value with pair.get(a) using another value a (which may not even exist since it depends on user input!).

Assuming you still want to achieve this functionality, you need to have something along these lines.

// Get the key referenced by a (if exists)
var aKey = pair.entrySet()
               .stream()
               .filter(entry -> a.equals(entry.getValue()))
               .map(Map.Entry::getKey)
               .findFirst();

// If the key for value a does not exist, print incorrect input (you can handle this however you like), otherwise print original statement
if (aKey.isEmpty()) {
    System.out.println("Incorrect input!");
} else {
    System.out.println(a.equals(pair.get(values[retur])) ? "Correct answer." :
                        "Wrong answer. The correct one is \"" + pair.get(values[retur]) +
                                "\", you've just written the definition of \"" + pair.get(aKey.get())  + "\".");
}

Upvotes: 0

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