Reputation: 1159
I have a data.table
in R
. I have to decrement date from last variable within by group. So in the example below, the date "2012-01-21" should be the 10th row when id = "A" and then decrement until the 1st row. and then for id="B" the date should be "2012-01-21" for 5th row and then decrement by 1 until it reaches first row. Basically the the decrement should start from last value by "id". How could I accomplish in R
data.table
?
The code below does the opposite. The date starts from 1st row and decrements, how would you start the date by last row and then decrement.
end<- as.Date("2012-01-21")
dt <- data.table(id = c(rep("A",10),rep("B",5)),sales=10+rnorm(15))
dtx <- dt[,date := seq(end,by = -1,length.out = .N),by=list(id)]
> dtx
id sales date
1: A 12.008514 2012-01-21
2: A 10.904740 2012-01-20
3: A 9.627039 2012-01-19
4: A 11.363810 2012-01-18
5: A 8.533913 2012-01-17
6: A 10.041074 2012-01-16
7: A 11.006845 2012-01-15
8: A 10.775066 2012-01-14
9: A 9.978509 2012-01-13
10: A 8.743829 2012-01-12
11: B 8.434640 2012-01-21
12: B 9.489433 2012-01-20
13: B 10.011354 2012-01-19
14: B 8.681002 2012-01-18
15: B 9.264915 2012-01-17
Upvotes: 1
Views: 35
Reputation: 388807
We could reverse the sequence generated above.
library(data.table)
dt[,date := rev(seq(end,by = -1,length.out = .N)),id]
dt
# id sales date
# 1: A 10.886312 2012-01-12
# 2: A 9.803543 2012-01-13
# 3: A 9.063694 2012-01-14
# 4: A 9.762628 2012-01-15
# 5: A 8.764109 2012-01-16
# 6: A 11.095826 2012-01-17
# 7: A 8.735148 2012-01-18
# 8: A 9.227285 2012-01-19
# 9: A 12.024336 2012-01-20
#10: A 9.976514 2012-01-21
#11: B 8.488753 2012-01-17
#12: B 9.141837 2012-01-18
#13: B 11.435365 2012-01-19
#14: B 10.817839 2012-01-20
#15: B 8.427098 2012-01-21
Similarly,
dt[,date := seq(end - .N + 1,by = 1,length.out = .N),id]
Upvotes: 1