CODEWITHSUNDEEP
javaparsingint
mango
mango

Reputation: 3

How to raise an int in a string in Java?

I am making a storybook and, because I'm not very creative with names, I gave images page numbers like so.

ImageIcon pg1icon = new ImageIcon("images/1.png");
ImageIcon pg2icon = new ImageIcon("images/2.png");
ImageIcon pg3icon = new ImageIcon("images/3.png");

JLabel pg1Label = new JLabel(pg1icon);
JLabel pg2Label = new JLabel(pg2icon);
JLabel pg3Label = new JLabel(pg3icon);

Because I have 30 pages, this process is getting tedious. Is there a way to scale the page num similar to i++?

Upvotes: 0

Views: 55

Answers (2)

Elliott Frisch
Elliott Frisch

Reputation: 201439

Assuming you only need the ImageIcon for the JLabel, you could use one array to store your thirty JLabel(s). Like,

int pageCount = 30;
JLabel[] labels = new JLabel[pageCount];
for (int i = 0; i < pageCount; i++) { // <-- i++ as requested
    ImageIcon icon = new ImageIcon(String.format("images/%d.png", 1+i));
    labels[i] = new JLabel(icon);
}

And then use labels[0] - labels[29] instead of pg1Label - pg30Label.

Upvotes: 1

Tim Biegeleisen
Tim Biegeleisen

Reputation: 521178

Using streams we can handle this requirement concisely as:

List<JLabel> labels = IntStream.rangeClosed(1, 30)
    .mapToObj(i -> new JLabel(new ImageIcon("images/" + i + ".png")))
    .collect(Collectors.toList());

Upvotes: 3

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