CODEWITHSUNDEEP
matlabmathnumerical-methodsnumerical-analysistaylor-series
therevovo
therevovo

Reputation: 13

My code for Taylor series graphs cos(2x) instead of cos(x) in Matlab

I'm writing a function that calculates the Taylor series of any Function.

syms  x
y=cos(x);
y0=0;
a=0;
for i=0:25
      diff(y,i);                                %%Gives the derivative formula
      y0=y0+diff(y,i)*((x-a)^i)/factorial(i);   %%sums every new element of the series
end

x=0:0.1:2*pi;
res = subs(y0,x);
plot(x,res,x,cos(x))

This is the Matlab code.

My problem is that it graphs cos(2x) instead of cos(x), similarly it graphs ln(2x) instead of ln(x) and so on.

I have checked the factorials and they appear to be correct. What could be the problem, have I messed up the series or have I made a Matlab mistake?

Upvotes: 1

Views: 813

Answers (1)

Lutz Lehmann
Lutz Lehmann

Reputation: 26040

You are constructing the Taylor polynomial around the point x with incrementx-a, that is, you are computing an approximation for

f(x+(x-a))=f(2*x-a)

Now as a=0, this means that as observed, you get f(2*x).

You would need to evaluate the derivatives at a to get the correct coefficients. 

y0=y0+subs(diff(y,i),a)*((x-a)^i)/factorial(i);   %%sums every new element of the series

Upvotes: 2

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