Reputation: 11
I'm reviewing the security of an app for a University project, the app encrypts a file using RSA, specifically it uses this library: https://github.com/ilansmith/rsa (DO NOT use this, it has serious vulnerabilities).
(If you want to take a look, most of the operations between these numbers are implemented in the rsa_num.c
file.)
This tool uses arrays of unsigned long long
to store the big numbers needed for RSA (n
, e
and d
):
typedef struct {
u64 arr[17]; //u64 is defined as unsigned long long
int top; //points to the last occupied slot of the array
} u1024_t;
The problem is that I don't understand how the numbers are stored in this format. What I need is being able to print the real numbers in some way, or at least a way to recover the numbers from the components of the arrays.
I tried just concatenating them like strings, but it doesn't seem right.
Thanks to whoever will be able to help!
Upvotes: 0
Views: 93
Reputation: 11
Thank you @Matthieu! Your comment worked.
I needed to concatenate the unsigned long long
s in reverse order and reversing their bytes due to endianness.
Following his solution, I implemented this function, which works perfectly:
void print_u1024(u1024_t number) {
int size = (number.top + 1) * sizeof(u64);
for (int i = size-1; i >= 0; i--) {
printf("%02x", ((unsigned char*)number.arr)[i]);
}
printf("\n");
}
Please note that this solution will probably only work on little-endian systems (most PCs).
Upvotes: 1