Reputation: 7461
I need to remove time portion of date time or probably have the date in following format in object
form not in the form of string
.
06/26/2009 00:00:00:000
I can not use any string
conversion methods as I need the date in object
form.
I tried first converting the DateTime
to a string
, remove the time specific date from it, but it adds 12:00:00 AM
as soon as I convert it back to DateTime
object
back again.
Upvotes: 624
Views: 1315506
Reputation: 1813
Since .NET 6 you can do this:
var dateOnly = DateOnly.FromDateTime(dateTime);
Upvotes: 14
Reputation: 11
When comparing/searching Use .Date
on both side. For example:
return await _context.KWhLog.Where(e => e.DateAndTime.Date ==
(shortDateValue.Date)).ToListAsync();
The time parameter will be ignored.
Upvotes: 1
Reputation: 2576
Use the method ToShortDateString
. See the documentation http://msdn.microsoft.com/en-us/library/system.datetime.toshortdatestring.aspx
var dateTimeNow = DateTime.Now; // Return 00/00/0000 00:00:00
var dateOnlyString = dateTimeNow.ToShortDateString(); //Return 00/00/0000
Upvotes: 144
Reputation: 1453
You can use a Date library like https://www.nuget.org/packages/Date/ to work with Date values, convert them to and from DateTimes, etc.
Disclaimer I'm the author of the above package.
Upvotes: 0
Reputation: 383
Add Date
property to the DateTime
variable
var dateTime = DateTime.Now
var onlyDate = dateTime.Date
Or You can use DataType
annotation as well.
[DataType(DataType.Date)]
public DateTime dateTime {get; set;}
The DataType annotation is inside the System.ComponentModel.DataAnnotations
namespace.
Upvotes: 7
Reputation: 3412
var newDate = DateTime.Now; //newDate.Date property is date portion of DateTime
Upvotes: 12
Reputation: 8704
You can use format strings to give the output string the format you like.
DateTime dateAndTime = DateTime.Now;
Console.WriteLine(dateAndTime.ToString("dd/MM/yyyy")); // Will give you smth like 25/05/2011
Read more about Custom date and time format strings.
Upvotes: 222
Reputation: 111
In case you would want to use Binding and show only Date portion without time
ToolTip="{Binding TransactionModel.TransactionDate, StringFormat=d}"
Upvotes: 0
Reputation: 21
To get only the date portion use the ToString() method,
example: DateTime.Now.Date.ToString("dd/MM/yyyy")
Note: The mm in the dd/MM/yyyy format must be capitalized
Upvotes: 2
Reputation: 89
I think you would this: DateTime onlyDate = DateTime.Today.Date; or, that's the same DateTime onlyDate = yourDateTime.Date; So use the property Date.
Upvotes: 0
Reputation: 119
Use date.ToShortDateString() to get the date without the time component
var date = DateTime.Now
var shortDate = date.ToShortDateString() //will give you 16/01/2019
use date.ToString() to customize the format of the date
var date = DateTime.Now
var shortDate = date.ToString('dd-MMM-yyyy') //will give you 16-Jan-2019
Upvotes: 8
Reputation: 3365
The Date
property will return the date at midnight.
One option could be to get the individual values (day/month/year) separately and store it in the type you want.
var dateAndTime = DateTime.Now;
int year = dateAndTime.Year;
int month = dateAndTime.Month;
int day = dateAndTime.Day;
string.Format("{0}/{1}/{2}", month, day, year);
Upvotes: 30
Reputation: 32719
Create a struct that holds only the properties you want. Then an extension method to easily get that struct from an instance of DateTime.
public struct DateOnly
{
public int Day { get; set; }
public int Month { get; set; }
public int Year { get; set; }
}
public static class DateOnlyExtensions
{
public static DateOnly GetDateOnly(this DateTime dt)
{
return new DateOnly
{
Day = dt.Day,
Month = dt.Month,
Year = dt.Year
};
}
}
Usage
DateTime dt = DateTime.Now;
DateOnly result = dt.GetDateOnly();
Upvotes: 2
Reputation: 843
Try this, if you use a DateTimeOffset
, it will also take care of the timezone
date1 = date1.LocalDateTime.Date;
If you need to add hours, use this:
date1 = date1.LocalDateTime.Date;
date1 = date1.AddHours(23).AddMinutes(59).AddSeconds(59);
Upvotes: 1
Reputation: 29
If you want to remove part of time from a DateTime
, try using this code:
DateTime dt = new DateTime();
dt = DateTime.Now; //ex: 31/1/2017 6:30:20 PM
TimeSpan remainingTime = new TimeSpan(0, dt.Hour - 5, dt.Minute - 29, dt.Second - 19);
dt=dt.Add(remainingTime);
label1.Text = dt.ToString("HH:mm:ss"); // must be HH not hh
the output : 01:01:01
Upvotes: 0
Reputation: 6607
Here is another method using String.Format
DateTime todaysDate = DateTime.UtcNow;
string dateString = String.Format("{0:dd/MM/yyyy}", todaysDate);
Console.WriteLine("Date with Time: "+ todaysDate.ToString());
Console.WriteLine("Date Only : " + dateString);
Output:
Date with Time: 9/4/2016 11:42:16 AM
Date Only : 04/09/2016
This also works if the Date Time is stored in database.
For More Date and Time formatting check these links:
Hope helps.
Upvotes: 12
Reputation: 27342
I wrote a DateOnly
structure. This uses a DateTime under the skin but no time parts are exposed publically:
using System;
public struct DateOnly : IComparable, IFormattable, IComparable<DateOnly>, IEquatable<DateOnly>
{
private DateTime _dateValue;
public int CompareTo(object obj)
{
if (obj == null)
{
return 1;
}
DateOnly otherDateOnly = (DateOnly)obj;
if (otherDateOnly != null)
{
return ToDateTime().CompareTo(otherDateOnly.ToDateTime());
}
else
{
throw new ArgumentException("Object is not a DateOnly");
}
}
int IComparable<DateOnly>.CompareTo(DateOnly other)
{
return this.CompareToOfT(other);
}
public int CompareToOfT(DateOnly other)
{
// If other is not a valid object reference, this instance is greater.
if (other == new DateOnly())
{
return 1;
}
return this.ToDateTime().CompareTo(other.ToDateTime());
}
bool IEquatable<DateOnly>.Equals(DateOnly other)
{
return this.EqualsOfT(other);
}
public bool EqualsOfT(DateOnly other)
{
if (other == new DateOnly())
{
return false;
}
if (this.Year == other.Year && this.Month == other.Month && this.Day == other.Day)
{
return true;
}
else
{
return false;
}
}
public static DateOnly Now()
{
return new DateOnly(DateTime.Now.Year, DateTime.Now.Month, DateTime.Now.Day);
}
public static bool TryParse(string s, ref DateOnly result)
{
DateTime dateValue = default(DateTime);
if (DateTime.TryParse(s, out dateValue))
{
result = new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
return true;
}
else
{
return false;
}
}
public static DateOnly Parse(string s)
{
DateTime dateValue = default(DateTime);
dateValue = DateTime.Parse(s);
return new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
}
public static DateOnly ParseExact(string s, string format)
{
CultureInfo provider = CultureInfo.InvariantCulture;
DateTime dateValue = default(DateTime);
dateValue = DateTime.ParseExact(s, format, provider);
return new DateOnly(dateValue.Year, dateValue.Month, dateValue.Day);
}
public DateOnly(int yearValue, int monthValue, int dayValue) : this()
{
Year = yearValue;
Month = monthValue;
Day = dayValue;
}
public DateOnly AddDays(double value)
{
DateTime d = new DateTime(this.Year, this.Month, this.Day);
d = d.AddDays(value);
return new DateOnly(d.Year, d.Month, d.Day);
}
public DateOnly AddMonths(int months)
{
DateTime d = new DateTime(this.Year, this.Month, this.Day);
d = d.AddMonths(months);
return new DateOnly(d.Year, d.Month, d.Day);
}
public DateOnly AddYears(int years)
{
DateTime d = new DateTime(this.Year, this.Month, this.Day);
d = d.AddYears(years);
return new DateOnly(d.Year, d.Month, d.Day);
}
public DayOfWeek DayOfWeek
{
get
{
return _dateValue.DayOfWeek;
}
}
public DateTime ToDateTime()
{
return _dateValue;
}
public int Year
{
get
{
return _dateValue.Year;
}
set
{
_dateValue = new DateTime(value, Month, Day);
}
}
public int Month
{
get
{
return _dateValue.Month;
}
set
{
_dateValue = new DateTime(Year, value, Day);
}
}
public int Day
{
get
{
return _dateValue.Day;
}
set
{
_dateValue = new DateTime(Year, Month, value);
}
}
public static bool operator == (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() == aDateOnly2.ToDateTime());
}
public static bool operator != (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() != aDateOnly2.ToDateTime());
}
public static bool operator > (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() > aDateOnly2.ToDateTime());
}
public static bool operator < (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() < aDateOnly2.ToDateTime());
}
public static bool operator >= (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() >= aDateOnly2.ToDateTime());
}
public static bool operator <= (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() <= aDateOnly2.ToDateTime());
}
public static TimeSpan operator - (DateOnly aDateOnly1, DateOnly aDateOnly2)
{
return (aDateOnly1.ToDateTime() - aDateOnly2.ToDateTime());
}
public override string ToString()
{
return _dateValue.ToShortDateString();
}
public string ToString(string format)
{
return _dateValue.ToString(format);
}
public string ToString(string fmt, IFormatProvider provider)
{
return string.Format("{0:" + fmt + "}", _dateValue);
}
public string ToShortDateString()
{
return _dateValue.ToShortDateString();
}
public string ToDbFormat()
{
return string.Format("{0:yyyy-MM-dd}", _dateValue);
}
}
This is converted from VB.NET, so apologies if some conversions are not 100%
Upvotes: 6
Reputation: 526
Getting the Date
part of a DateTime
object didn't workout for me because I'm working on the client-side and the returned web service values have some null
dates. As a result, it tries to get the Date part of a null value and it throws a runtime exception. The following example is how I solved my problem:
string dt = employer.BirthDay.ToString();
if(dt == ""){ dt = "N/A";}
else dt = dt.Substring(0,10);
DateTime
value and assign it to the string variable.I'm sharing this for future reference.
Upvotes: 1
Reputation: 367
This code gives you a clear view of writing Date
as well as Time
separately
string time = DateTime.Now.Hour.ToString("00") + ":" + DateTime.Now.Minute.ToString("00") + ":" + DateTime.Now.Second.ToString("00");
string date = DateTime.Now.ToString("M-dd-yyyy");
MessageBox.Show(date + "\n" + time);
Hope this helps.
Upvotes: 1
Reputation: 2563
static void Main(string[] args)
{
string dateStrings = "2014-09-01T03:00:00+00:00" ;
DateTime convertedDate = DateTime.Parse(dateStrings);
Console.WriteLine(" {0} ----------------- {1}",
convertedDate,DateTime.Parse(convertedDate.ToString()).ToString("dd/MM/yyyy"));
Console.Read();
}
Upvotes: 1
Reputation: 89
This way of get only date without time
DateTime date = DateTime.Now;
string Strdateonly = date.ToString("d");
Output = 5/16/2015
Upvotes: 7
Reputation: 17849
I know this is an old post with many answers, but I haven't seen this way of removing the time portion. Suppose you have a DateTime
variable called myDate
, with the date with time part. You can create a new DateTime
object from it, without the time part, using this constructor:
public DateTime(int year, int month, int day);
Like this:
myDate = new DateTime(myDate.Year, myDate.Month, myDate.Day);
This way you create a new DateTime
object based on the old one, with 00:00:00 as time part.
Upvotes: 4
Reputation: 11
For using by datalist, repeater.. in aspx page:<%# Eval("YourDateString").ToString().Remove(10) %>
Upvotes: 1
Reputation: 331
If you are converting it to string, you can easily do it like this.
I'm taking date as your DateTime object.
date.ToString("d");
This will give you only the date.
Upvotes: 5
Reputation: 4391
Use a bit of RegEx:
Regex.Match(Date.Now.ToString(), @"^.*?(?= )");
Produces a date in the format: dd/mm/yyyy
Upvotes: 1
Reputation: 11
Use .Date of a DateTime object will ignore the time portion.
Here is code:
DateTime dateA = DateTime.Now;
DateTime dateB = DateTime.Now.AddHours(1).AddMinutes(10).AddSeconds(14);
Console.WriteLine("Date A: {0}",dateA.ToString("o"));
Console.WriteLine("Date B: {0}", dateB.ToString("o"));
Console.WriteLine(String.Format("Comparing objects A==B? {0}", dateA.Equals(dateB)));
Console.WriteLine(String.Format("Comparing ONLY Date property A==B? {0}", dateA.Date.Equals(dateB.Date)));
Console.ReadLine();
Output:
>Date A: 2014-09-04T07:53:14.6404013+02:00
>Date B: 2014-09-04T09:03:28.6414014+02:00
>Comparing objects A==B? False
>Comparing ONLY Date property A==B? True
Upvotes: 1
Reputation: 19
Declare the variable as a string.
example :
public string dateOfBirth ;
then assign a value like :
dateOfBirth = ((DateTime)(datetimevaluefromDB)).ToShortDateString();
Upvotes: 1
Reputation: 51
I'm surprised no one has mentioned DateTime.Today
var date = DateTime.Today;
// {7/1/2014 12:00:00 AM}
See MSDN
Upvotes: 5
Reputation: 3945
Came across this post when trying to solve the original Q.
I am using Asp.Net and after some research I have found when you are binding to the value of the date in code behind, you can drop the time so it will not display on screen.
C#:
DateTime Today = DateTime.Now;
aspx:
<%: this.Today.ToShortDateString() %>
Upvotes: 2