CODEWITHSUNDEEP
javascriptarraystypescript
rawrstar
rawrstar

Reputation: 165

Search array, find elements with ids specified another array, extract a property from the results

I have two arrays,

array1 = [{name: "a", id: 1},{name: "b", id: 2},{name: "c", id: 3}]

and 

array2 = [1, 2] // --which are the ids

I want to return a new array (array3) to display ["a", "b"] and if array2 = [1,3] then array3 should be ["a", "c"]

In other words, I would like to create a new array, with the names, corresponding to its id.

Upvotes: 1

Views: 41

Answers (3)

gsthina
gsthina

Reputation: 1100

I would go ahead and perform the below:

for(int i = 0; i<array1.length(); ++i){
  for(int j = 0; j<array2.length(); ++j){
    if (array1[i].id==array2[j]){
      array3[j] = array[i].name;
    }
  }
}

Hope this is simple and it helps!

Upvotes: 1

Brian Lee
Brian Lee

Reputation: 18197

You can use reduce:

let a1 = [{name:'a', id:1},{name:'b', id:2},{name:'c', id:3}]
let a2 = [1,3]

let a3 = a1.reduce((carry, current) => {
    if (a2.includes(current.id)) {
        carry.push(current.name)
    }
    
    return carry
}, [])

alert(a3)

Upvotes: 1

Arash Motamedi
Arash Motamedi

Reputation: 10682

User filter to select the elements that meet your criteria, and map to get the property you want. 

const array1 = [{name:"a", id:1},{name:"b", id:2},{name:"c", id:3}];
const array2=[1,2];
const array3 = array1.filter(i => array2.includes(i.id)).map(i => i.name);

array3 will contain ["a", "b"]

Upvotes: 1

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