CODEWITHSUNDEEP
mysqlsqlsql-order-bysql-like
Alex Cross
Alex Cross

Reputation: 33

Multiple LIKE Operator ORDER BY Strongest

I have the following query:

SELECT * FROM table_name
WHERE (genre LIKE '%romance%'
    OR genre LIKE '%comedy%'
    OR genre LIKE '%horror%')
ORDER BY *the column that has more*

OR SOMETHING LIKE THAT

$sql = "SELECT * FROM table WHERE
(genre LIKE '%romance%' AND genre LIKE '%comedy%' AND genre LIKE '%horror%')
#If result < 12
(genre LIKE '%romance%' AND genre LIKE '%comedy%') OR (genre LIKE '%romance%' AND genre LIKE '%horror%') OR (genre LIKE '%comedy%' AND genre LIKE '%horror%')
#If result < 12
(genre LIKE '%romance%' OR genre LIKE '%comedy%' OR genre LIKE '%horror%')";

I mean if there is a movie has these three genres I want to get it first else I get movie which has romance and comedy or romance and horror or comedy and horror.

Upvotes: 0

Views: 138

Answers (1)

Barmar
Barmar

Reputation: 781300

A conditional operator returns 1 when it's true, 0 when it's false. So add up the number of matches.

ORDER BY (genre LIKE '%romance%')
        + (genre LIKE '%comedy%')
        + (genre LIKE '%horror%') DESC

DEMO

It would be better to normalize your tables. Add a table movie_genre like

CREATE TABLE movie_genre (
    movie_id INT(11) NOT NULL, # foreign key to movie.id
    genre_id INT(11) NOT NULL  # foreign key to genre.id
);

Then you would do a query like:

SELECT m.* 
FROM movie AS m
JOIN movie_genre AS mg ON m.id = mg.movie_id
JOIN genre AS g ON g.id = mg.genre_id
WHERE g.name IN ('comedy', 'romance', 'horror')
GROUP BY m.id
ORDER BY COUNT(*) DESC

Upvotes: 5

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