CODEWITHSUNDEEP
pythonpython-3.xpandascsv
yen936
yen936

Reputation: 53

How to flip a csv rows order while keeping headers?

I would like to be able to flip a csv file rows but keep the headers.

Current

timestamp       open      high       low     close     volume
2020-04-14 2805.1001 2851.8501 2805.1001 2846.0601 3113388741
2020-04-13 2782.4600 2782.4600 2721.1699 2761.6299 5274310000
 .....
2000-01-04 1455.2200 1455.2200 1397.4301 1399.4200 1009000000
2000-01-03 1469.2500 1478.0000 1438.3600 1455.2200 931800000

Desired Result

timestamp       open      high       low     close     volume
2000-01-03 1469.2500 1478.0000 1438.3600 1455.2200 931800000
2000-01-04 1455.2200 1455.2200 1397.4301 1399.4200 1009000000
.....
2020-04-13 2782.4600 2782.4600 2721.1699 2761.6299 5274310000
2020-04-14 2805.1001 2851.8501 2805.1001 2846.0601 3113388741

I have been able to flip the data over with this, but I cannot retain the headers. Skip headers is added, else the headers are put on the bottom of the csv file.

Current Code

 def reverse_csv():
    with open("spx.csv", "r") as infile, open("spx_cleaned.csv", "w") as outfile:
    reader = csv.reader(infile)
    next(reader, None)  # skip the headers
    writer = csv.writer(outfile)
    for row in reversed(list(reader)):
        # process each row
        writer.writerow(row)

Thanks!

Upvotes: 2

Views: 585

Answers (3)

Allen Qin
Allen Qin

Reputation: 19957

Can you try the following?

pd.read_csv('input.csv').iloc[::-1].to_csv('output.csv', index=False)

Upvotes: 2

pi_pascal
pi_pascal

Reputation: 202

Try 

import pandas as pd 

df = pd.read_csv('spx.csv')
df = df[::-1].reset_index(drop=True)
df.to_csv('spx_cleaned.csv')

Upvotes: 0

user13093119
user13093119

Reputation:

Simply use iloc:

df.iloc[::-1]

Upvotes: 0

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