CODEWITHSUNDEEP
pythonnetworkxgraphvizpygraphviz
jason
jason

Reputation: 4429

pygraphviz or networkx: getting the name of all subgraphs given node

I want to know the subgraph structure for a given node.

I'm ok with a networkx solution also.

Here is my code.

import pygraphviz as pgv

class Test:
    subgraph1 = 'foo'
    subgraph2 = 'bar'

    def __init__(self):
        self.G = pgv.AGraph(directed=True)
        self.G.add_subgraph(label=self.subgraph1, name='cluster_' + self.subgraph1)

        s1 = self.G.get_subgraph('cluster_' + self.subgraph1)
        s1.add_subgraph(label=self.subgraph2, name='cluster_' + self.subgraph2)
        s1.add_node('s1 node')

        s2 = s1.get_subgraph('cluster_' + self.subgraph2)
        s2.add_node('s2 node')

    def main(self):
        print(self.G.subgraph('1st node'))
        print(self.G.subgraph_parent('1st node'))
        print(self.G.subgraph_root('1st node'))
        n = self.G.get_node('1st node')
        print(n.attr['subgraph'])
        print(n.attr['label'])


if __name__ == '__main__': Test().main()

I want a function that will return me a list of subgraphs given any node in the entire graph. Something like this...

In: subgraph_structure_as_list('s2 node')

Out: ['foo', 'bar']

In: subgraph_structure_as_list('s1 node')

Out: ['foo']

Upvotes: 2

Views: 331

Answers (1)

Mojtaba Kamyabi
Mojtaba Kamyabi

Reputation: 3600

You can use a recursive approach like this:

import pygraphviz as pgv

class Test:
    subgraph1 = 'foo'
    subgraph2 = 'bar'

    def __init__(self):
        self.structure = []
        self.G = pgv.AGraph(directed=True)
        self.G.add_subgraph(label=self.subgraph1, name='cluster_' + self.subgraph1)

        s1 = self.G.get_subgraph('cluster_' + self.subgraph1)
        s1.add_subgraph(label=self.subgraph2, name='cluster_' + self.subgraph2)
        s1.add_node('s1 node')

        s2 = s1.get_subgraph('cluster_' + self.subgraph2)
        s2.add_node('s2 node')

    #  ... other methods here ...

    def get_structure(self, node_name, node=None):
        if node is None:
            node = self.G
        for subgraph in node.subgraphs():
            if node_name in subgraph.nodes():
                self.structure.append(subgraph.node_attr['label'])
            self.get_structure(node_name, subgraph)

    def subgraph_structure_as_list(self, node_name):
        self.structure = []
        self.get_structure(node_name)
        return self.structure

you can use the subgraph_structure_as_list as you want like this:

a = Test()
print(a.subgraph_structure_as_list('s2 node'))
print(a.subgraph_structure_as_list('s1 node'))

Output:

['foo', 'bar']
['foo']

Upvotes: 1

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