CODEWITHSUNDEEP
javascriptregex
Udendu Abasili
Udendu Abasili

Reputation: 1213

Using Regex in javascript to find all occurrance all up to but excluding the particular string

So basically given this string iiisdoso i want to extract all the part of the string before but excluding the letter o. So basically iiisd and s. I current just have 

const data = "iiisdoso"
const regex = /(.*?)o/g

console.log(data.match(regex))

but this result includes the o in but my goal is return results up to but excluding o

Upvotes: 0

Views: 38

Answers (1)

Arno
Arno

Reputation: 447

As already mentioned in the comments you can achieve this with negations and character classes:

const data = "iiisdoso"
const regex = /([^o]+)/g

console.log(data.match(regex))

This will give you the desired result

["iiisd", "s"]

But this does match any string with no "o" after it too! To avoid this, you need to use

const regex = /([^o]+)o/g

In this case the "o" is included in the matches and must be deleted for each string the result-array - e.g. with 

mymatch.replace('o','')

Interesting: If you use 

const regex = /([^o]*)/g

The result is

["iiisd", "", "s", "", ""]

This is something I don't understand. Well - I understand that an empty string matches the regex too and can be placed right before the "o". But why do we get a third empty string at the very end?

Upvotes: 1

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