CODEWITHSUNDEEP
javaarraysstring
poudandane
poudandane

Reputation: 9

Find char from string

I am begener with JAVA.

I have a STRING String text = "un essai de méthode"; //this text can be change by the user And I have a key word String key = "de"; //this Key word can also be changed by the user

As we can see, the key word "de" is present twice in the text: "un essai de méthode" And i need to count the number of times the key word repeats in the text.

int j = 0;
        int nbCharKey, nbCharText;
        int count = 0;
        int c;

        String text = "un essai de méthode do"; /*here is my text */
        String key = "de"; /*here is my key word */

        text = text.replaceAll(" ",""); /*i ignored all the spaces*/

        nbCharText = text.length(); /* length of my text to create a ARRAY */
        Character[] tabTEXT = new Character[nbCharText]; /*creating ARRAY for text */
        for (int a = 0; a < nbCharText; a++){ 
            tabTEXT[a]=text.charAt(a); /*adding the text into ARRAY*/
        }

        nbCharKey = key.length(); /* length of my key word to create a ARRAY */
        Character[] tabKEY = new Character[nbCharKey]; /*creating ARRAY for key word */
        for (int b = 0; b < nbCharKey; b++){
            tabKEY[b] = key.charAt(b); /*adding my key word into ARRAY*/
        }

        int verif = 0; /*helps to count nb times the 1st char of key word repeats*/

        char fKey = tabKEY[0];
        for (int d = 0; d < nbCharText; d++){

            if (fKey==tabTEXT[d]){
               verif++; /*the 1st key letter "d" is found twice*/
            }

            //I DO NOT KNOW HOW TO CONTINUE THE REST
            //I DO NOT KNOW HOW TO CONTINUE THE REST
            //I DO NOT KNOW HOW TO CONTINUE THE REST
            //I DO NOT KNOW HOW TO CONTINUE THE REST
            if (fKey==tabTEXT[d]){
                Character[] word = new Character[nbCharKey];

                for(int e = 0; e<nbCharKey; e++){
                    word[e]=tabTEXT[d];
                    //System.out.println(nbCharKey);
                    System.out.println(word[e]);
                    d++;

                }
            }

Please help me.

Thanks in advance.

Upvotes: 1

Views: 80

Answers (1)

jurabek rashidov
jurabek rashidov

Reputation: 112

 String text = "un essai de méthode";
        char[] charArrayText = text.toCharArray();

        String key = "de";
        char[] charArrayKey = key.toCharArray();

        int count = 0;
        boolean check = true;
        for (int i = 0; i < charArrayText.length; i++) {
            for (int j = 0; j < charArrayKey.length; j++) {
                if (charArrayText[i + j] != charArrayKey[j] || i == charArrayText.length - 1) {
                    check = false;
                    break;
                }
            }
            if (check) {
                count++;
            }
            check = true;
        }

        System.out.println(count);

Upvotes: 2

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