Reputation: 1169
With the query, I basically want to compare avg_clicks at different time periods and set a filter according to the avg_clicks
.
The below query gives us avg_clicks
for each shop in January 2020. But I want to see the avg_clicks
that is higher than 0
in January 2020.
Question 1: When I add the where avg_clicks > 0
in the query, I am getting the following error: Column 'avg_clicks'
cannot be resolved. Where to put the filter?
SELECT AVG(a.clicks) AS avg_clicks,
a.shop_id,
b.shop_name
FROM
(SELECT SUM(clicks_on) AS clicks,
shop_id,
date
FROM X
WHERE site = ‘com’
AND date >= CAST('2020-01-01' AS date)
AND date <= CAST('2020-01-31' AS date)
GROUP BY shop_id, date) as a
JOIN Y as b
ON a.shop_id = b.shop_id
GROUP BY a.shop_id, b.shop_name
Question 2: As I wrote, I want to compare two different times. And now, I want to see avg_clicks
that is 0 in February 2020.
As a result, the desired output will show me the list of shops that had more than 0 clicks in January, but 0 clicks in February.
Hope I could explain my question. Thanks in advance.
Upvotes: 0
Views: 49
Reputation: 1269503
Start with conditional aggregation:
SELECT shop_id,
SUM(CASE WHEN DATE_TRUNC('month', date) = '2020-01-01' THEN clicks_on END) / COUNT(DISTINCT date) as avg_clicks_jan,
SUM(CASE WHEN DATE_TRUNC('month', date) = '2020-02-01' THEN clicks_on END) / COUNT(DISTINCT date) as avg_clicks_feb
FROM X
WHERE site = 'com' AND
date >= '2020-01-01' AND
date < '2020-03-01'
GROUP BY shop_id;
I'm not sure what comparison you want to make. But if you want to filter based on the aggregated values, use a HAVING
clause.
Upvotes: 0
Reputation: 7503
For your Question 1
try to use having
clause. Read execution order of SQL statement which gives you a better idea why are you getting avg_clicks()
error.
SELECT AVG(a.clicks) AS avg_clicks,
a.shop_id,
b.shop_name
FROM
(SELECT SUM(clicks_on) AS clicks,
shop_id,
date
FROM X
WHERE site = ‘com’
AND date >= '2020-01-01'
AND date <= '2020-01-31'
GROUP BY shop_id, date) as a
JOIN Y as b
ON a.shop_id = b.shop_id
GROUP BY a.shop_id, b.shop_name
HAVING AVG(a.clicks) > 0
For your Question 2
, you can do something like this
SELECT
shop_id,
b.shop_name,
jan_avg_clicks,
feb_avg_clicks
FROM
(
SELECT
AVG(clicks) AS jan_avg_clicks,
shop_id
FROM
(
SELECT
SUM(clicks_on) AS clicks,
shop_id,
date
FROM X
WHERE site = ‘com’
AND date >= '2020-01-01'
AND date <= '2020-01-31'
GROUP BY
shop_id,
date
) as a
GROUP BY
shop_id
HAVING AVG(clicks) > 0
) jan
join
(
SELECT
AVG(clicks) AS feb_avg_clicks,
shop_id
FROM
(
SELECT
SUM(clicks_on) AS clicks,
shop_id,
date
FROM X
WHERE site = ‘com’
AND date >= '2020-02-01'
AND date < '2020-03-01'
GROUP BY
shop_id,
date
) as a
GROUP BY
shop_id
HAVING AVG(clicks) = 0
) feb
on jan.shop_id = feb.shop_id
join Y as b
on jan.shop_id = b.shop_id
Upvotes: 1