Reputation: 73
I am trying to implement a doubly linked list in C++ and have run across a problem.
#include <iostream>
#include <string>
struct Node
{
std::string data;
Node* prev_link;
Node* next_link;
Node(const std::string& data,Node* prev_link=nullptr, Node* next_link=nullptr)
: data{data},prev_link{prev_link},next_link{next_link} {}// constructor
};
Node* insert(Node* new_node,Node* old_node);// insert node before old node
Node* head(Node* node);// returns a pointer to the head i.e. the left end of the linked list
void print_list(Node* node);//takes the head pointer and executes iterative print
void kill_list(Node* tail_node);// deallocates memory by deleting the list
Node* insert(Node* new_node,Node* old_node)
{
if(new_node == nullptr) return old_node;
if(old_node == nullptr) return new_node;
new_node->next_link = old_node;// p of old node connect to new node
if(old_node->prev_link) old_node->prev_link->next_link = new_node;//n of old' node connect to new node if old' node exists
new_node->prev_link = old_node->prev_link;//p of new node connect to old` node
new_node->next_link = old_node;//n of new node connect to old node
return new_node;
}
Node* head(Node* node)
{
while(node->next_link != nullptr) node = node->next_link;
return node;
}
void print_list(Node* node)
{
while(node)
{
std::cout << node->data;
if(node = node->next_link) std::cout << "<->";// if next node is not an end node
}
}
void kill_list(Node* tail_node)
{
Node* temp;
while (tail_node)
{
temp = (tail_node->prev_link)?tail_node->prev_link:tail_node->next_link;
delete tail_node;
tail_node = temp;
}
std::cout << '\n' <<"List destroyed" << std::endl;
}
int main()
{
Node* alphabets = new Node("A");
alphabets = insert(new Node("B"),alphabets);
alphabets = insert(new Node("C"),alphabets);
print_list(alphabets);
std::cout << '\n';
std::cout << "Head:" << head(alphabets)->data << std::endl;
std::cout << "Adjacent:" << head(alphabets)->prev_link->data << std::endl;
kill_list(alphabets);
}
output:
C<->B<->A
Head:A
fish: “./test1” terminated by signal SIGSEGV (Address boundary error)
The head() function returns a pointer to the head node(in this case it's A). The linked list as well as the head node is printed correctly but I cannot access the node adjacent to the head node. Cannot figure out what I am doing wrong. Any help would be appreciated.
Upvotes: 2
Views: 118
Reputation: 364
The problem is due to the fact that the prev_link is not set for the head (the prev link is zero for every node), there is an error on the insert function, you never set the prev_link of the old node.
Upvotes: 0
Reputation: 1838
Your error is because there is a null pointer for the neighbor of A
. In your insert function, you have this if statement
if(old_node->prev_link) old_node->prev_link->next_link = new_node
However, in the case of A
, there is no prev_link
but you would still like to assign B
. So replacing that with:
old_node->prev_link = new_node;
fixes the issue. However you might want to double check so that this corresponds to your desired logic.
Upvotes: 2