Reputation: 1278
I need a class extending datetime.date
adding logic that is relevant to my application. It used to work well with Python 2, but I don't understand how to write the constructor in Python 3. I thought the standard way to write a derived constructor in Python 3 was like this:
from datetime import date
class my_date(date):
def __init__(self, year, month, day):
super().__init__(year, month, day)
date(2020, 4, 18)
my_date(2020, 4, 18)
However, this code fails with:
Traceback (most recent call last):
File "/tmp/test.py", line 8, in <module>
my_date(2020, 4, 18)
File "/tmp/test.py", line 5, in __init__
super().__init__(year, month, day)
TypeError: object.__init__() takes exactly one argument (the instance to initialize)
What should I do to properly call the super constructor?
In particular, datetime.date
clearly accepts to be initialized with three numbers. Why does the error message say it takes one argument? And why is the problem in object.__init__()
instead of in datetime.date.__init__()
?
Upvotes: 3
Views: 942
Reputation: 1
If you want to extend date then you can do something like this.
from datetime import date
class MyDate(date):
def __init__(self, year, month, day):
print(self)
print(date(2020, 4, 18))
print(MyDate(2020, 4, 20))
Upvotes: -1
Reputation: 51683
Answer from the comments:
Looking at the Python source of datetime.date you’ll notice that it doesn’t have an
__init__()
method, only a__new__()
constructor. That would explain the above error. Also note thatyear
,month
,day
are decorated (i.e. read only) properties, not instance values.
Replace
super().__init__(year, month, day)
withpass
from datetime import date
class my_date(date):
pass
d1 = date(2020, 4, 18)
d2 = my_date(2020, 4, 18)
print(d1,d2)
Outputs:
2020-04-18 2020-04-18
You might think about using composition instead of inheritance for whatever you need done:
class MyDateClass:
def __init__(self, a_date):
self.my_date = a_date
# add members/methods that do stuff wiht a_date
instead of inheriting date.
See
Upvotes: 3