Reputation: 37
I have a dataframe that contains a column with dates e.g. 24/07/15 etc Is there a way to create a new column into the dataframe that displays all the days of the week corresponding to the already existing 'Date' column?
I want the output to appear as: [Date][DayOfTheWeek]
Upvotes: 1
Views: 375
Reputation: 34046
This might work:
In [1405]: df
Out[1405]:
dates
0 24/07/15
1 25/07/15
2 26/07/15
In [1406]: df['dates'] = pd.to_datetime(df['dates']) # You don't need to specify the format also.
In [1408]: df['dow'] = df['dates'].dt.day_name()
In [1409]: df
Out[1409]:
dates dow
0 2015-07-24 Friday
1 2015-07-25 Saturday
2 2015-07-26 Sunday
In [1410]: df['dow'] = df['dates'].dt.day
In [1411]: df
Out[1411]:
dates dow
0 2015-07-24 24
1 2015-07-25 25
2 2015-07-26 26
Upvotes: 1
Reputation: 2819
Depending of the type of you column Date.
df['Date']=pd.to_datetime(df['Date'], format="d/%m/%y")
df['weekday'] = df['Date'].dt.dayofweek
Upvotes: 0
Reputation: 56
I would try the apply function, so something like this:
def extractDayOfWeek(dateString):
...
df['DayOfWeek'] = df.apply(lambda x: extractDayOfWeek(x['Date'], axis=1)
The idea is that, you map over every row, extract the 'date' column, and then apply your own function to create a new row entry named 'Day'
Upvotes: 0