CODEWITHSUNDEEP
phplaravellaravel-6
foi56497
foi56497

Reputation: 1

Laravel keeps giving me: "Undefined offset 2"

I try foreach loop but it keeps giving me "Undefined offset 2".

I tried also isset then I got "Undefined offset 1"

My code:

foreach ($lineArrayResults as $lineArrayResultKey => $lineArrayResult)
{
    $currentFormFieldId = $submittedFormFields[$lineArrayResultKey]; // this line gives me error.
    if($currentFormFieldId > 0)
    {
        $newLeadDataArray[$currentFormFieldId] = [
            'field_name' => $formFields[$currentFormFieldId],
            'field_value' => $lineArrayResult
        ];
    }
}

Upvotes: 0

Views: 377

Answers (2)

A N M Mahabubul Hasan
A N M Mahabubul Hasan

Reputation: 1596

the error undefined offset means that an array have ran out of bounds. the array size is smaller than the index that you are trying to fetch an object from.

First of all make sure your $submittedFormFields array contains the key of $lineArrayResultKey variable, if the array key is dynamically generated then try this code

foreach ($lineArrayResults as $lineArrayResultKey => $lineArrayResult)
{
    if(!array_key_exists($lineArrayResultKey, $submittedFormFields)){
        continue;
    }

    $currentFormFieldId = $submittedFormFields[$lineArrayResultKey];
    if($currentFormFieldId > 0)
    {
        $newLeadDataArray[$currentFormFieldId] = [
            'field_name' => $formFields[$currentFormFieldId],
            'field_value' => $lineArrayResult
        ];
    }
}

Upvotes: 1

Hossein Piri
Hossein Piri

Reputation: 812

add @ before $ try this

foreach ($lineArrayResults as $lineArrayResultKey => $lineArrayResult)
{
    $currentFormFieldId = @$submittedFormFields[$lineArrayResultKey]; // insert @ before $
    if($currentFormFieldId > 0)
    {
        $newLeadDataArray[$currentFormFieldId] = [
            'field_name' => $formFields[$currentFormFieldId],
            'field_value' => $lineArrayResult
        ];
    }
}

Upvotes: 0

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