CODEWITHSUNDEEP
c++
Alessandra D. Simmons
Alessandra D. Simmons

Reputation: 1

Is there a way to make one class equal to another in C++?

I'm trying to write a layer for making some components of a project more modular. How can I make a class Foo exactly equal to a class Bar, where Foo would be able to be used as the variable 'a' in a function int testFunc(Bar a)?

Would the only solution be to have Foo have a definition like this?

class Foo {
public:
    Foo(int a) : barReturn(a) {};
    operator Bar() const { return barReturn; }
private:
    Bar barReturn;
};

Upvotes: 0

Views: 397

Answers (2)

上山老人
上山老人

Reputation: 462

May be you can use the polymorphism of c++.There are some diffrent components derived an interface Foo.

class Foo {
public:
    virtual Foo(int a);
    virtual Update(int a);
};

class Bar1 : public Foo{
public:
    virtual Bar1(int a): m_a(a);
    virtual Update(){
        // TODO:
    }
private:
    int m_a;
};

class Bar2 : public Foo{
public:
    virtual Bar1(int a): m_b(a);
    virtual Update(){
        // TODO:
    }
private:
    int m_b;
};

// There a module to do Foo
void ProcessModule(){
    std::vector<Foo*> v;
    v.push_back(new Bar1(1));
    v.push_back(new Bar2(2));

    for (std::vector<Foo*>::itreator it = v.begin(); v != v.end(); ++v){
        it->UPdate()
    }
}

Upvotes: 0

Jarod42
Jarod42

Reputation: 218333

If you want a true alias, you might do an alias:

since C++11:

using Foo = Bar;

or the old way (still valid):

typedef Bar Foo;

Upvotes: 1

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