CODEWITHSUNDEEP
arrayskotlin
Ferhad Mehdizade
Ferhad Mehdizade

Reputation: 163

Divide to Size of array in Kotlin, but I get zero, even size of array equals to 1 or more

    fun plusMinus(arr: Array<Int>): Unit {
    var counterPositive = 0
    var counterNegative = 0
    var counterZero = 0
    for(i in 0 until arr.size) {
        if(arr[i] > 0) {
            counterPositive++
        } else if(arr[i] < 0) {
            counterNegative++
        } else {
            counterZero++
        }
    }

    println(counterPositive)
    println(arr.size)
    val a = counterPositive/arr.size
    println(a)
}

I try to solve simple algorithm question, but I face this interesting thing. So, i try to find positive, negative numbers, and zeros in array. And each one divide to size of array. And print it But i get 0 as result. But when i debug code i see that counterPositive is for example 4 and arr.size for example 5 but i get 0. Why?

Upvotes: 0

Views: 560

Answers (1)

Giorgio Antonioli
Giorgio Antonioli

Reputation: 16224

You get zero since counterPositive, counterNegative and counterZero are initialized with 0 so the type Int is inferred.

Since the array size is an Int, the division between two Int results in an Int.

To fix it, you'd need to use a Float or a Double.

val a = counterPositive.toFloat() / arr.size

Upvotes: 5

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