CODEWITHSUNDEEP
c++
Imad
Imad

Reputation: 7490

Use variable from outer function from inside inner function

My code that contains function inside another function as shown below:

ReturnType OuterFunction(someParameters, MyType* mt)
{
   function<OtherType*(parameterList)> innerFunction = 
   [this](parameterList)
   {
      return someOtherFunction(someParameters, mt);
   }
}

I have added a parameter MyType to someOtherFunction and modified it's call as seen in above code.

mt is the variable that is passed from OuterFunction and I am not able to use it inside someOtherFunction.

It is giving me an error

An enclosing-function local variable cannot be referenced in a lambda body unless if it is in the capture list.

Upvotes: 1

Views: 957

Answers (1)

MrDiver
MrDiver

Reputation: 122

You have to add mt to your capture list in the lambda youre trying to use there.

By default you have no access to outside variables. And adding this is adding a Pointer to your object.

ReturnType OuterFunction(T s1, K s2, MyType* mt)
{
   function<OtherType*(parameterList)> innerFunction = 
   [s1,s2,mt](parameterList)
   {
      return someOtherFunction(s1, s2, mt);
   }
}

You can take a look at this https://learn.microsoft.com/en-us/cpp/cpp/lambda-expressions-in-cpp?view=vs-2019

Upvotes: 2

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