CODEWITHSUNDEEP
c++
Captain Jack sparrow
Captain Jack sparrow

Reputation: 1019

Getting error: ISO C++ forbids declaration of ‘type name’ with no type

I have a nested class definition and get errors on applying a cast to the pointer to it. The following program compiles with the error:

test.cpp: In member function ‘void* Achild<T>::test(void*)’:
test.cpp:24:31: error: ISO C++ forbids declaration of ‘type name’ with no type [-fpermissive]
       ShortName::ptr = (const ShortName::Ptr*)input;
                               ^~~~~~~~~
test.cpp:24:25: error: expected primary-expression before ‘const’
       ShortName::ptr = (const ShortName::Ptr*)input;
                         ^~~~~
test.cpp:24:25: error: expected ‘)’ before ‘const’
       ShortName::ptr = (const ShortName::Ptr*)input;
                        ~^~~~~
                         )
test.cpp:25:6: warning: no return statement in function returning non-void [-Wreturn-type]
      }

I can't understand why i am getting errors on line 24. Any help would be appreciated!

template<typename T>
   class VeryLongName
   {
     public:
         class Ptr
         {
                 public:
                         int a;
                         Ptr() = default;
         };
         const Ptr* ptr;

   };

   template <typename T>
   class Achild: public VeryLongName<T>
   {
     using ShortName = VeryLongName<T>;
   public:
     Achild<T>() = default;

     void test(void * input)
     {
             ShortName::ptr = (const ShortName::Ptr*)input;
     }

   };

int main()
{
        auto *achild = new Achild<int>();
        auto a = new VeryLongName<int>::Ptr();
        achild->test((void*)a);
}

Upvotes: 3

Views: 4647

Answers (1)

Thomas Caissard
Thomas Caissard

Reputation: 866

You are missing a typename declaration:

ShortName::ptr = (const typename ShortName::Ptr*) input;

as ShortName depends on your template type.

Upvotes: 7

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