CODEWITHSUNDEEP
scala
Mark
Mark

Reputation: 2071

is there any elegant way to return None rather that object based on string

Is there any elegant way to return None rather than an object if the string inputted is empty?

bellow is a crude example of what I want to achieve

private def foo(input: String): Option[Object] = {
   Some(Object(input)) //return None instead if input is empty
}

*PS : What I mean by elegant is for me to not create/define another function to achieve this

Upvotes: 1

Views: 264

Answers (3)

iris
iris

Reputation: 381

For completeness, following @jwvh answer, Option.unless uses the negated predicate as declared in Option.when,

private def foo(input: String): Option[Object] = {
   Option.unless(input.isEmpty)(Object(input))
}

Upvotes: 1

C4stor
C4stor

Reputation: 8036

def foo(input: String): Option[Object] =
  if(input.nonEmpty)
    Some(Object(input))
  else
    None

It will be instantly parsed by anyone reading your code, so really, it doesn't get better than that.

Upvotes: 1

jwvh
jwvh

Reputation: 51271

Scala 2.13.x offers the Option.when() method.

def foo(input: String): Option[Object] =
  Option.when(input.nonEmpty)(Object(input))

Upvotes: 5

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