Reputation: 1381
I have a list of ids arr = [123, 456, 765...]
I need to do a for each of these:
I need to run a bunch of steps like grabbing some values from a MongoDB collection, then converting that into a list, and then making a change to the returned fields and inserting them back to a new collection.
How do I do this for a forEach of the id's in that list.
Here is the rest of functions I am running:
hello=col.find({'id':123}, {'_id':0})
for item in hello:
to_ISO = datetime.strptime(item['created_dt'], "%Y-%m-%dT%H:%M:%S.%f%z")
list_audits = list(audit_pages_res)
pprint(list_audits)
db.newcol.insert({date: to_ISO})
I want to do a forEach from arr
, replace the id
in hello
do the rest of the functions I need and then insert the record and then move to the next item on the list.
Is there any way for me to do that?
Upvotes: 0
Views: 28
Reputation: 8814
Hard to figure out exactly what you're trying to do but if you know the exact _id then no need to use a find and a loop; just use find_one()
. start with:
arr = [123, 456, 765]
for arr_id in arr:
hello=col.find_one({'id':arr_id}, {'_id':0})
if hello is not None: # Need to check it found a record
to_ISO = datetime.strptime(hello['created_dt'], "%Y-%m-%dT%H:%M:%S.%f%z")
Upvotes: 1