Reputation: 2270
I am making a game where when you touch the wall, you have to click a rectangle to move on.
However, the rectangle is displayed, but so is the previous screen.
I can't use screen.fill((0, 0, 0))
because in the loop, it will just keep going.
I want to delete the screen(or withdraw it temporarily. This is preferred).
Here is my code:
import pygame
pygame.init()
clock = pygame.time.Clock()
screen = pygame.display.set_mode((400, 300))
done = False
x = 100
y = 100
#button1 = pygame.draw.rect(screen, (0, 0, 255), (200, 200, 30, 30))
#if check <= pos - (w/2) and check >=
pygame.display.set_caption("Auto Maze!")
donk = False
while not done:
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
if event.type == pygame.MOUSEBUTTONDOWN:
mouse = event.pos
try:
assert button1.collidepoint(mouse)
except AssertionError:
pass
except NameError:
pass
else:
donk = True
pressed = pygame.key.get_pressed()
if pressed[pygame.K_w]:
y -= 5
elif pressed[pygame.K_s]:
y += 5
elif pressed[pygame.K_a]:
x -= 5
elif pressed[pygame.K_d]:
x += 5
screen.fill((0, 0, 0))
try:
assert player.colliderect(wall1)
except AssertionError:
pass
except NameError:
pass
else:
death_screen = pygame.display.set_mode((400, 300))
button1 = pygame.draw.rect(death_screen, (0, 0, 255), (200, 200, 30, 30))
if donk:
break
player = pygame.draw.rect(screen, (0, 255, 0), (x, y, 60, 60))
wall1 = pygame.draw.rect(screen, (255, 0, 0), (400, 300, -100, -300))
clock.tick(60)
pygame.display.flip()
quit()
Thanks in advance!!
Upvotes: 0
Views: 485
Reputation: 2110
I got rid of the try and except and i think it does what you want
player = pygame.draw.rect(screen, (0, 255, 0), (x, y, 60, 60))
wall1 = pygame.draw.rect(screen, (255, 0, 0), (300, 0, 100, 300))
if player.colliderect(wall1):
death_screen = pygame.display.set_mode((400, 300))
button1 = pygame.draw.rect(death_screen, (0, 0, 255), (200, 200, 30, 30))
if donk:
break
Upvotes: 1