CODEWITHSUNDEEP
phpevalsyntax-error
andrewtweber
andrewtweber

Reputation: 25509

Unexpected $end in eval()'d code

I hate to ask such a specific question, but I'm getting an error I can't figure out. This is in a cron job which runs on the hour. I'm creating an array of tasks, each of which has a date check which is supposed to be eval()'d.

$todo = array();
$todo[] = array( "date('z')%3 == 0", "Task 1" );
$todo[] = array( "date('N') == 1", "Task 2" );
foreach( $todo as $task )
{
    if( eval($task[0]) ) {
        echo $task[1];
    }
}

For some reason the eval() line is giving me this error. Note that I am getting this error for both tasks.

Parse error: syntax error, unexpected $end in /file.php(21) : eval()'d code on line 1

Any suggestions? I tried searching for this but couldn't find anything. Thank you.

Upvotes: 15

Views: 33881

Answers (2)

Tomero Indonesia
Tomero Indonesia

Reputation: 1695

You are missing ';' on end of string evaluation. Eval function able to process statements or expressions.

Example:

$value = 7;
eval("\$value+=2;");
echo $value;

Upvotes: 5

mario
mario

Reputation: 145482

eval only accepts statements, not expressions. You need to convert your tests with:

if (eval("return $task[0];")) {

Upvotes: 31

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