Reputation: 12418
What's a simple way to check if an item is in a list?
Something like
(in item list)
might return true
if item=1
and list=(5 9 1 2)
and false
if item=7
Upvotes: 37
Views: 63544
Reputation: 139251
Common Lisp
FIND
is not a good idea:
> (find nil '(nil nil))
NIL
Above would mean that NIL
is not in the list (NIL NIL)
- which is wrong.
The purpose of FIND
is not to check for membership, but to find an element, which satisfies a test (in the above example the test function is the usual default EQL
). FIND
returns such an element.
Use MEMBER
:
> (member nil '(nil nil))
(NIL NIL) ; everything non-NIL is true
or POSITION
:
> (numberp (position nil '()))
NIL
Upvotes: 51
Reputation: 3689
Use MEMBER
to test whether an item is in a list:
(member 1 '(5 9 1 2)) ; (1 2)
Unlike FIND
, it is also able to test whether NIL
is in the list.
Upvotes: 24
Reputation: 28703
You can use find
:
(find 1 '(5 9 1 2)) ; 1
(find 7 '(5 9 1 2)) ; nil
Consider using :test
argument:
(find "a" '("a" "b") :test #'equal)
Upvotes: 10