How would I make the char # repeat such that it will show the given figure in c?

Question

I want to make a program for an exercise in the CS50 course that asks the user to input the height of the figure and then makes a figure that is similar to:

       #
      ##
     ###
    ####
   #####
  ######
 #######
########

considering the user inputs height 8.

I have the code:

#include <stdio.h>
#include <cs50.h>

int main(void)
{
    int height;

    do
    {
        height = get_int("Enter The Height: ");
    }
    while (!(2 <= height && height<=8));

    for (int row = 1; row <= height; row++)
    {

        for (int column = 1; column <= height; column++)
        {
            printf("#");
        }
        printf("\n");
    }
}

but it prints this:

###
###
###

when I give height 3.

I am a beginner in the C language and so won't understand the advanced concepts, so I request a simple explanation, please.

Answer 1

Shorter is better.

#include <stdio.h>

int main(void) {
    int height = 5;
    char blocks[height];
    memset(blocks, '#', height);
    for(int i=0; i<height; ++i)
    {
        printf("%*.*s\n", height, i+1, blocks);
    }
    return 0;
}

Answer 2

Here you are.

#include <stdio.h>

int main(void) 
{
    const char c = '#';

    while ( 1 )
    {
        printf( "Enter The Height (0 - exit): " );

        int n;

        if ( scanf( "%d", &n ) != 1 || n <= 0 ) break;

        putchar( '\n' );

        for ( int i = 0; i < n; i++ )
        {
            printf( "%*c", n - i, c );
            for ( int j = 0; j < i; j++ ) putchar( c );
            putchar( '\n' );
        }

        putchar( '\n' );
    }

    return 0;
}

The program output might look like

Enter The Height (0 - exit): 10

         #
        ##
       ###
      ####
     #####
    ######
   #######
  ########
 #########
##########

Enter The Height (0 - exit): 9

        #
       ##
      ###
     ####
    #####
   ######
  #######
 ########
#########

Enter The Height (0 - exit): 8

       #
      ##
     ###
    ####
   #####
  ######
 #######
########

Enter The Height (0 - exit): 7

      #
     ##
    ###
   ####
  #####
 ######
#######

Enter The Height (0 - exit): 6

     #
    ##
   ###
  ####
 #####
######

Enter The Height (0 - exit): 5

    #
   ##
  ###
 ####
#####

Enter The Height (0 - exit): 4

   #
  ##
 ###
####

Enter The Height (0 - exit): 3

  #
 ##
###

Enter The Height (0 - exit): 2

 #
##

Enter The Height (0 - exit): 1

#

Enter The Height (0 - exit): 0

As for your code then you are always outputting the same number of the symbol '#' with no indentations.

    for (int column = 1; column <= height; column++)
    {
        printf("#");
    }

You can change your loops the following way

    for (int row = 1; row <= height; row++)
    {

        for (int column = 1; column <= height; column++)
        {
            putchar( column < height - row + 1 ? c2 : c1 );
        }
        printf("\n");
    }

where c1 is equal to '#' and c2 is equal to ' '.

Here is another demonstrative program

#include <stdio.h>

int main(void) 
{
    const char c1 = '#', c2 = ' ';

    while ( 1 )
    {
        printf( "Enter The Height (0 - exit): " );

        int height;

        if ( scanf( "%d", &height ) != 1 || height <= 0 ) break;

        putchar( '\n' );

        for (int row = 1; row <= height; row++)
        {

            for (int column = 1; column <= height; column++)
            {
                putchar( column < height - row + 1 ? c2 : c1 );
            }
            printf("\n");
        }

        putchar( '\n' );
    }

    return 0;
}

Its output might look like

Enter The Height (0 - exit): 9

       #
      ##
     ###
    ####
   #####
  ######
 #######
########

Enter The Height (0 - exit): 0