CODEWITHSUNDEEP
python-3.xamazon-web-servicesaws-lambda
Cadell Teng
Cadell Teng

Reputation: 244

AWS Lambda Execution result: failed

I've written a lambda function in the AWS Lambda GUI. The program I've written will send me an email, the program appears to work but there is error in my logs and I cannot even begin to understand those errors. I like to seek help on how to resolve the error.

This is the error I've gotten:

{
  "errorMessage": "2020-04-27T07:22:08.185Z b6ec9468-75c2-4e39-aeeb-bd0085758fb8 Task timed out after 3.00 seconds"
}

This is the log output

START RequestId: b6ec9468-75c2-4e39-aeeb-bd0085758fb8 Version: $LATEST
END RequestId: b6ec9468-75c2-4e39-aeeb-bd0085758fb8
REPORT RequestId: b6ec9468-75c2-4e39-aeeb-bd0085758fb8  Duration: 3003.16 ms    Billed Duration: 3000 ms    Memory Size: 128 MB Max Memory Used: 50 MB  Init Duration: 122.21 ms    
2020-04-27T07:22:08.185Z b6ec9468-75c2-4e39-aeeb-bd0085758fb8 Task timed out after 3.00 seconds

And my code is below (mail-demo.py)

import os
import smtplib

def main(event, context):
    # TODO implement
    EMAIL_ADDRESS = os.environ['EMAIL_ADD']
    EMAIL_PASSWORD = os.environ['EMAIL_PWD']

    with smtplib.SMTP('smtp.gmail.com', 587) as smtp:
        smtp.ehlo()
        smtp.starttls()
        smtp.ehlo()

        smtp.login(EMAIL_ADDRESS, EMAIL_PASSWORD)

        subject = 'Wassup!'
        body = 'Testing some lambda function at don\'t know what time'

        msg = f'Subject: {subject}\n\n{body}'

        smtp.sendmail(EMAIL_ADDRESS, EMAIL_ADDRESS, msg)

    return 'email sent success'

Upvotes: 0

Views: 693

Answers (1)

Marcin
Marcin

Reputation: 238199

You have to increase your functions execution timeout:

Timeout – The amount of time that Lambda allows a function to run before stopping it. The default is 3 seconds. The maximum allowed value is 900 seconds.

Upvotes: 1

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