CODEWITHSUNDEEP
phpjquerypost
dancingbush
dancingbush

Reputation: 2281

POST to PHP with success but PHP code not executing

I am using JQuery post method to send data to a PHP script from an external JS script.

const Url2 = 'MainPage2.php?action=updatePurchaseToDB';
   const data = {
       name: "test name"
   }
   //takes 3 arg, url, data to sedn, call back function, data in callback holds the page reqeusted in data
   $.post(Url2,data, function(data, status){
       console.log('${data} and status is ${status}');
       alert("PHP Retrned form server:  Status " + status);
   });

This is the PHP code in MainPage2.php :

if ($_POST['action'] == 'updatePurchaseToDB'){
    echo "<script>console.log('UPDATE PURCHASE CALLED!');</script>";
    echo "PHP CALLED AS PURCHASE BUTTON PRESSED";
  }

The call back function returns a Success message but I can't see any evidence the PHP code has executed, that is nothing has printed to the console.

Is there something missing in my call to the PHP script?

Upvotes: 0

Views: 47

Answers (1)

Barmar
Barmar

Reputation: 781068

Since the action is in the URL, you need to access it with $_GET['action'], not $_POST['action']. If you want it in the POST data, you need to add it to the data object:

const data = {
    action: "updatePurchaseToDB",
    name: "test name"
}

Your console.log() call is not substituting the variables correctly. You need to use backticks to create a template literal.

   $.post(Url2,data, function(data, status){
       console.log(`${data} and status is ${status}`);
       alert("PHP Returned form server:  Status " + status);
   });

Upvotes: 2

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