Reputation: 2254
People can sign into my app anonymously:
FirebaseAuth.instance.signInAnonymously();
Once inside, they have a little indicator that reminds them if they want be able to save their data across phones, they'll need to sign in. For Google authentication that looks like this:
Future<void> anonymousGoogleLink() async {
try {
final user = await auth.currentUser();
final credential = await googleCredential();
await user.linkWithCredential(credential);
} catch (error) {
throw _errorToHumanReadable(error.toString());
}
}
where googleCredential
is:
Future<AuthCredential> googleCredential() async {
final googleUser = await _googleSignIn.signIn();
if (googleUser == null) throw 'User Canceled Permissions';
final googleAuth = await googleUser.authentication;
final signInMethods = await auth.fetchSignInMethodsForEmail(
email: googleUser.email,
);
if (signInMethods.isNotEmpty && !signInMethods.contains('google.com')) {
throw 'An account already exists with the same email address but different sign-in credentials. Sign in using a provider associated with this email address.';
}
return GoogleAuthProvider.getCredential(
accessToken: googleAuth.accessToken,
idToken: googleAuth.idToken,
);
}
Now I'd like to do the same thing but instead link the current anonymous account with email and password authentication.
Found a possible solution while writing this. Leaving for others to possibly see. Feel free to correct me.
Upvotes: 2
Views: 1542
Reputation: 2254
On the FirebaseUser
object the method updatePassword
has this doc string:
/// Updates the password of the user.
///
/// Anonymous users who update both their email and password will no
/// longer be anonymous. They will be able to log in with these credentials.
/// ...
You should just be able to update both and then they'll be authenticated as a regular user. For me that looked like:
Future<void> anonymousEmailLink({
@required FirebaseUser user,
@required String email,
@required String password,
}) async {
try {
await Future.wait([
user.updateEmail(email),
user.updatePassword(password),
]);
} catch (error) {
throw _errorToHumanReadable(error.toString());
}
}
Upvotes: 4