CODEWITHSUNDEEP
julia
Aadithyaa Eeswaran
Aadithyaa Eeswaran

Reputation: 71

Why does Julia throw a premature end of input error when i write and if statement?

This is my code:

using Printf
using Statistics

age = 12
if age < 10
    println("$age")

This is the error:

ERROR: LoadError: syntax: incomplete: premature end of input
Stacktrace:
 [1] top-level scope at D:\julia\trial.jl:5
 [2] include(::Module, ::String) at .\Base.jl:377
 [3] exec_options(::Base.JLOptions) at .\client.jl:288
 [4] _start() at .\client.jl:484
in expression starting at D:\julia\trial.jl:5

It works well if I remove the if statement and just print the value of age.

Upvotes: 3

Views: 6384

Answers (1)

mbauman
mbauman

Reputation: 31342

Julia terminates its blocks with an end keyword (and does not rely on whitespace to define its blocks).

age = 12
if age < 10
    println("$age")
end

Upvotes: 9

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