Reputation: 29
If static local variable also stored in the data segment, why can't values are not persist for variable which is used in two different functions. example like this.
void func()
{
static int i=0;
i++;
}
void func1()
{
i++; // here i is stored in the data segment,
// then the scope should be available for entire program
}
Why the value 'i' is only accessible to block scope if is stored in data segment? it might be a silly question but I am trying to understand to concept. Please help me to understand concept. Thanks in advance.
Upvotes: 2
Views: 274
Reputation: 224092
A variable in C consists of two things:
For a variable declared inside a function, its identifier has block scope, and the identifier is visible only from its declaration to the }
that closes the innermost block it is in. (A block is a list of statements and declarations inside {
and }
.)
Inside a function, declaring a variable with static
makes its object have static storage duration, causing it to exist for all of program execution, but it does not change the scope of its identifier. The object exists throughout program execution, but the identifier is visible only inside the function.
When another function is called, the object still exists (and it can be used if the function has its address, perhaps because it has been passed as a parameter). However, the identifier for the variable is not known inside the source code of other functions, so they cannot use the identifier.
Upvotes: 0
Reputation: 12673
You need to differentiate between the scope and the lifetime of a variable.
In simple words:
"scope" means the region of your source code where the variable is known to the compiler. If a variable is (by the rules) not visible to the compiler, it will refuse to compile accesses to it.
"lifetime" means the time beginning with the allocation of memory for the variable until the moment the memory is assigned to another variable or released. A static
variable lives as long as the program runs. A non-static
variable lives just as long as its scope is in control.
However, just because both scope and lifetime of a variable are "finished", that does not mean that the memory disappears. The physical cells are still there, and they keep their last contents. That's why you can program functions that return a pointer to some local variable, and retrieve that variables contents after both the scope and the lifetime of the variable are gone. This is a fine example of a beginner's confusing issue.
Consider a compiler for an embedded processor like the 8051. Granted, a quite old and simple machine, but a good example. This compiler will commonly put local variables in its data segment. But to use the limited memory space (128 bytes in total, including working registers and stack) the same memory locations are re-used for variables with non-overlapping lifetimes. Eventhough, you could access any memory from all of the program.
Now, language lawyers, start picking on me. ;-)
Upvotes: 4