Reputation: 11
I'm on HackerRank and I need to remove duplicate items from a sorted linked list. I passed all the cases except for two of them which the input is something like: 10001102034 So my program takes to seconds to complete and exceed the time. How can I do my code more efficiently, I heard about using square root but I don't know how to use it. Any guide is appreciate. Here is my code.
private static Node removeDuplicates(Node head) {
/* Another reference to head */
Node current = head;
Node next;
/* Traverse list till the last node */
while (current != null && current.next != null) {
if (current.data == current.next.data) {
next = current.next.next;
if (next == null) {
current.next = null;
break;
}
current.next = next;
} else {
current = current.next;
}
}
return head;
}
Again. It works but takes too much times with longer numbers.
Upvotes: 0
Views: 119
Reputation: 19565
You should replace condition if (current.data == current.next.data)
with while
loop and use break 'label'
:
out:
while (current != null && current.next != null) {
while (current.data == current.next.data) {
next = current.next.next;
if (next == null) {
current.next = null;
break out;
}
current.next = next;
}
current = current.next;
}
Upvotes: 2
Reputation: 40
You can't use the square root because when u want to remove duplicates from a list you have to check all the list . The square root technique is used for searching in a sorted list. But for your question if you can improve the runtime on that your code in O(n^2) but if you change your code to use hashtable you can make it O(n).
import java.util.HashSet;
public class removeDuplicates
{
static class node
{
int val;
node next;
public node(int val)
{
this.val = val;
}
}
/* Function to remove duplicates from a
unsorted linked list */
static void removeDuplicate(node head)
{
// Hash to store seen values
HashSet<Integer> hs = new HashSet<>();
/* Pick elements one by one */
node current = head;
node prev = null;
while (current != null)
{
int curval = current.val;
// If current value is seen before
if (hs.contains(curval)) {
prev.next = current.next;
} else {
hs.add(curval);
prev = current;
}
current = current.next;
}
}
/* Function to print nodes in a given linked list */
static void printList(node head)
{
while (head != null)
{
System.out.print(head.val + " ");
head = head.next;
}
}
I hope this will help you.
Upvotes: 0