CODEWITHSUNDEEP
pythonpyspark
2713
2713

Reputation: 195

Convert string column to date in pyspark

I've a dataframe where the date/time column is of string datatype and looks something like "Tue Apr 21 01:16:19 2020". How do I convert this to a date column with format as 2020/04/21 in pyspark. I tried something like this,

option1:

df = df.withColumn("event_time2",from_unixtime(unix_timestamp(col("Event_time"), 'MM/dd/yyy')))

option2:

df= df.withColumn("event_time2",unix_timestamp(col("Event_time"),'yyyy-MM-dd HH:mm:ss').cast("timestamp"))

but both return null

Upvotes: 1

Views: 263

Answers (1)

murtihash
murtihash

Reputation: 8410

You could use to_date and date_format. EEE is for day in the week. Refer to Java Simple Data Format for the complete list

from pyspark.sql import functions as F
df.withColumn("Event_time2", F.to_date("Event_time", 'EEE MMM dd HH:mm:ss yyyy')).show(truncate=False)

#+------------------------+-----------+
#|Event_time              |Event_time2|
#+------------------------+-----------+
#|Tue Apr 21 01:16:19 2020|2020-04-21 |
#+------------------------+-----------+


df.withColumn("Event_time2", F.date_format(F.to_date("Event_time", 'EEE MMM dd HH:mm:ss yyyy'),'yyyy/MM/dd')).show(truncate=False)

#+------------------------+-----------+
#|Event_time              |Event_time2|
#+------------------------+-----------+
#|Tue Apr 21 01:16:19 2020|2020/04/21 |
#+------------------------+-----------+

Upvotes: 1

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