CODEWITHSUNDEEP
asp.net-mvc-3routes
Chris Marisic
Chris Marisic

Reputation: 33098

MVC3 is it possible to serve a view section from a controller action?

Suppose I have index.cshtml

@{
    ViewBag.Title = "Index";
}
@model SomeModel

@section JS{     
    content1
    content2
    content3
}

<div> View Content </div>

Is there any way I could have a controller action that would serve ONLY the section JS for a request for index.js?

Such that navigating to http://somesite/index.js would return

    content1
    content2
    content3

Edit: Some further thoughts on this. My goal would be along the lines say creating a layout page that requires a JS section programmatically, and then composing the View to that layout page and then returning the results of this.

Psuedo code example:

var layout = new LayoutPage();
layout.DefineSection("JS", required: true);
layout.Compose(View("index"))
return layout;

I'm not set on achieving that with what I described but I feel that might offer some more insight on what I'd like to achieve.

Upvotes: 1

Views: 278

Answers (2)

Buildstarted
Buildstarted

Reputation: 26689

You can do something like this (but you'd have to write your own controller action to do it properly)

Index.cshml

@model MvcApplication1.Models.TestModel
@{
    ViewBag.Title = "Home Page";
}

<h2>@ViewBag.Message</h2>
<p>
    To learn more about ASP.NET MVC visit <a href="http://asp.net/mvc" title="ASP.NET MVC Website">http://asp.net/mvc</a>.
</p>

@section JS {
    blahblahblah
}

JSLayout:

@RenderSection("JS")

Your controller Action

public ActionResult Index() {
    return View("Index", "_JSLayout", yourModel);
}

This will output only the JS section. If you want to do it programatically then it will take a bit.

Upvotes: 1

AaronShockley
AaronShockley

Reputation: 851

The only way to do it would be to make the content of that section into a partial view, and return the partial view from the controller action.

Upvotes: 0

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