Reputation: 3734
I have this two elements a button and a dialog
<dialog className='w-11/12 shadow-none rounded-tl-md rounded-tr-md lg:rounded-lg absolute'>wqdwe</dialog>
<button className=" px-6 py-2 rounded absolute mt-12 ml-12" onClick={} >Click</button>
How can I open the dialog on clicking the button in React
constructor(props) {
super(props);
this.myRef = React.createRef();
}
showModals(){
this.myRef.showModal();
}
componentDidMount() {
//this.showModals()
}
EDIT: I am trying to access the .showModal()
method in the dialog according to MDN https://developer.mozilla.org/en-US/docs/Web/HTML/Element/dialog. How can I do that, I need the dimmed background feature when the modal is opened.
Upvotes: 1
Views: 2137
Reputation: 609
You do not need componentDidMount
nor useRef
with the state
and using the props open
of the dialog
you can show it conditionally.
isOpen
is the state
class Modal extends React.Component {
constructor(props) {
super(props);
}
render() {
return (
<dialog style={{width: "80%", height: "80%", marginTop: 10, backgroundColor: '#eee'}}
open={this.props.open}
>
<p>Greetings, one and all!</p>
</dialog>
);
}
}
class App extends React.Component {
constructor() {
super();
this.state = {
isOpen: false
};
}
switchModal = (prevState) => {
this.setState((prevState, props) => {
return { isOpen: !prevState.isOpen }
});
}
render() {
return (
<div>
<button onClick={this.switchModal}>
{this.state.isOpen ? 'Close' : 'Open'} Modal
</button>
<br/>
<Modal open={this.state.isOpen}/>
</div>
);
}
}
React.render(<App />, document.getElementById('root'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/0.13.0/react.min.js"></script>
<div id="root"></div>
showModal
method. With this method you can use the css property dialog::backdrop
.class Modal extends React.Component {
constructor(props) {
super(props);
}
render() {
return (
<dialog id='modal' style={{width: "80%", height: "80%", marginTop: 10, backgroundColor: '#eee'}}
>
<p>Greetings, one and all!</p>
<button onClick={this.props.closeModal}>
Close Modal
</button>
</dialog>
);
}
}
class App extends React.Component {
constructor() {
super();
this.state = {
isOpen: false
};
}
switchModal = (prevState) => {
this.setState((prevState, props) => {
if(!prevState.isOpen) {
document.getElementById('modal').showModal()
} else {
document.getElementById('modal').close()
}
return { isOpen: !prevState.isOpen }
});
}
render() {
return (
<div>
{!this.state.isOpen && <button onClick={this.switchModal}>
Open Modal
</button>}
<br/>
<Modal
closeModal={this.switchModal}
/>
</div>
);
}
}
React.render(<App />, document.getElementById('root'));
dialog {
height: 80%;
width: 80%
}
dialog::backdrop {
background: rgba(255,0,0,.25);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/0.13.0/react.min.js"></script>
<div id="root"></div>
Upvotes: 2
Reputation: 6403
You can use the React state API to show and hide components based on actions taken elsewhere in the code.
class MyComponent extends React.Component {
constructor() {
this.state = {
isDialogVisible: false
}
}
handleClick = () => {
this.setState({ isDialogVisible: !this.state.isDialogVisible })
}
render() {
const { isDialogVisible } = this.state
return (
<div>
<Button onClick={this.handleClick}>{isDialogVisible ? 'Hide' : 'Show'} dialog</Button>
{this.state.isDialogVisible && <Dialog />}
</div>
)
}
}
Upvotes: 0