CODEWITHSUNDEEP
python
Abdelhamed Abdin
Abdelhamed Abdin

Reputation: 594

how can I loop this code until being equating to zero?

I need to solve this problem I have a parameter call num, this parameter is a number consist of number that has one column or more like 1 or 222 or 33 so on. for instance, if I typed 39 the number will multiplication as following 3 * 9 to equal to 27 which consists of two columns are 2 and 7 therefore I'll multiplication 2 * 7 to be 14 the end of this process the number will be consist of one column is 4. when a number will be equal to one column I will edit the num to be 0 I need just to loop this process many and many times until the remaining one column to be equal to zero how can I do so?

this is my function 

def presistance(num):
    mult = 1
    arr = []
    i = 0

    # check if num > 9
    while True:
        # numbers in array
        if num > 9:
            for n in str(num):
                arr.append(int(n))
            for n in arr:
                mult *= n  
            return mult
        else:
            num = 0
            return num

print(presistance(39))

Upvotes: 0

Views: 652

Answers (1)

pinkfluffyunicorn
pinkfluffyunicorn

Reputation: 91

Instead of returning mult you can simply set num equal to mult. Then the code will loop again in the while loop and check the next case and keep going until num only has one digit.

while True:
        # numbers in array
        mult = 1
        arr = []
        if num > 9:
            for n in str(num):
                arr.append(int(n))
            for n in arr:
                mult *= n  
            num = mult
            print(num)
        else:
            num = 0
            return num

Upvotes: 1

Related Questions