Reputation:
I'm building an app that fetches JSON-data from the OpenWeatherMap API. In my app I have structs like these:
struct WeatherData: Decodable {
let name: String
let main: Main
let coord: Coord
}
struct Main: Decodable {
let temp: Double
}
struct Coord: Decodable {
let lon: Double
let lat: Double
}
In one of my print statements, I want to print out all the values from Coords in the one print statement, like this print(decodedData.coord.lat)
How should I format the print statement so it can print both the lat
value and the lon
value?
Upvotes: 0
Views: 511
Reputation: 271800
The print
accepts a Any...
as its first parameter. The first sentence in the documentation says:
You can pass zero or more items to the
print(_:separator:terminator:)
function.
That means you can pass in any number of arguments in that position, and they will all get printed out:
print(decodedData.coord.lat, decodedData.coord.lon)
The two things will be separated by a space by default. You can pass in a separator:
argument to specify what separator you want.
Upvotes: 1