Reputation: 11
This is my bark
function using return
. When I call it, I am calling it four times but I only get the value of the last function which is bark("lady", 17);
and if I use this function with just console.log
instead of return
, then it will show me all four result.
Why is this happening and why can’t I see the result of all function calls?
function bark(name, weight) {
var barkVoice;
if (weight > 20) {
barkVoice = name + " says WOOF WOOF";
} else {
barkVoice = name + " says woof woof";
}
return barkVoice;
}
bark("rover", 23);
bark("spot", 13);
bark("spike", 53);
bark("lady", 17);
Upvotes: 0
Views: 97
Reputation: 10849
This happens because your environment is probably a console. It usually takes the last expression and prints it.
If you run
console.log(bark("rover", 23));
console.log(bark("spot", 13));
console.log(bark("spike", 53));
console.log(bark("lady", 17));
It should behave as you want it to.
Upvotes: 1