Reputation: 49
I am trying to consolidate data from multiple tabs into a consolidated sheet. Each tab is an individual form and has the same format. On the consolidated sheet, I want to re-arrange the data so the data field name is in a column, and data values are in rows. I tried the following:
function consolidateData(){
// defined all variables
var sheetNames = [];
var dataSheet = [];
var dataValues = [];
var conso=[];
var header = [["Faculty Name","Faculty ID","Date of Joining"]];
var ws = SpreadsheetApp.getActiveSpreadsheet();
// get all sheets
var allsheets = ws.getSheets();
for(var s in allsheets)
var sheet = allsheets[s];
sheetNames[s] = sheet.getName();
dataSheet[s] = ws.getSheetByName(sheetNames[s]);
// writing data into new sheet
var newSheet = ws.insertSheet().setName("Consolidated_Data");
newSheet.getRange("A1:C1").setValues(header);
var name = dataSheet[s].getRange("B1").getValue();
var id = dataSheet[s].getRange("B3").getValue();
var doj = dataSheet[s].getRange("B5").getValue();
var faculty = [(name),(id),(doj)];//convert into array
var facultycount = faculty.length;
for (var i = 0; i < faculty.length; i++)
//Loop through all rows and write them out starting on ROW2
{
newSheet.getRange(2 + i, 1).setValue(faculty[0]);//
newSheet.getRange(2 + i, 2).setValue(faculty[1]);//
newSheet.getRange(2 + i, 3).setValue(faculty[2]);//
}
}
There are four tabs and I expect to see results from each tab in the Consolidated_Data tab. But I only saw the last tab data got inserted repeatedly. Can anyone help? Thank you. Consolidated Data Sheet Example of an individual tab
Upvotes: 1
Views: 407
Reputation: 526
While traversing through all your sheets, you haven't used curly braces after the for loop -
for(var s in allsheets)
So it's running the loop and the value of s
stays at the last index of allsheets
.
However, might I suggest a simplified version I have tested out -
function consolidateData () {
const headers = ["Faculty Name", "Faculty ID", "Date of joining"];
const rows = { "name": 0, "id": 2, "doj": 4 };
const consolidatedSheetName = "Consolidated_Data";
const ss = SpreadsheetApp.getActive();
const sheets = ss.getSheets();
let consolidatedValues = [];
// Setting headers
consolidatedValues.push(headers);
// Fetching values
for(let sheet of sheets) {
if(sheet.getName()==consolidatedSheetName) { continue; }
let data = sheet.getRange("B1:B5").getValues();
let faculty = [ data[rows.name][0], data[rows.id][0], data[rows.doj][0] ];
consolidatedValues.push(faculty);
}
// Adding to sheet
let consolidatedSheet = ss.getSheetByName(consolidatedSheetName);
if(!consolidatedSheet) {
consolidatedSheet = ss.insertSheet().setName(consolidatedSheetName);
}
let range = consolidatedSheet.getRange(1, 1, consolidatedValues.length, consolidatedValues[0].length); // 1, 1, 3, 3
range.setValues(consolidatedValues);
}
Upvotes: 2
Reputation: 50445
The script is overwriting the same range here:
newSheet.getRange(2 + i, 1).setValue(faculty[0]);
Add 1 for each row added:
newSheet.getRange(2 + i + s, 1).setValue(faculty[0]);
Or use sheet#appendRow()
newSheet.appendRow(faculty);
If you practice best practices, Your script can be simplified like this:
const consolidate = () => {
const ws = SpreadsheetApp.getActiveSpreadsheet(),
oldSheets = ws.getSheets(),
newSheet = ws.insertSheet().setName('Consolidated_Data');
newSheet.getRange(1, 1, 1 + oldSheets.length * 3, 3).setValues([
['Faculty Name', 'Faculty ID', 'Date of Joining'],
...oldSheets.map(sheet =>
sheet
.getRange('B1:B5')
.getValues()
.reduce((a, c, i) => (i % 2 === 0 ? [...a, c[0]] : a), [])
),
]);
};
Upvotes: 1