CODEWITHSUNDEEP
pythonpandasdataframe
pylearner
pylearner

Reputation: 1460

am trying to check if a value in a dictionary is an integer or not

am trying to check if a value in a dictionary is an integer or not.

I have something like

d = {'number' : '1-', 'name' : 'A'}

am trying to see if the value of number is an integer after removing the '-'

Code:

d['number'] = d['number'].replace('-','')

so now its showing me d = {'number' : '1', 'name' : 'A'} here the value of number is again a string. But i want to check if the string is a number or an alphabet.

number can be of '12121' or 'rdrr'

How do I check if it has only digits ?

Upvotes: 0

Views: 4138

Answers (3)

user13051721
user13051721

Reputation:

If you need both key and value:

d = {'number' : '1', 'name' : 'A'}

digits = {}
for key, value in d.items():
  if value.isdigit():
    digits[key] = value

If you need just key:

digits = [key for key, value in d.items() if value.isdigit()]

Result of :

print(digits)

for 1st solution:

{'number': '1'}

for 2nd solution:

['number']

Upvotes: 0

tayken
tayken

Reputation: 127

You can use isdigit() and isalpha() functions. isdigit() returns "True" if all characters in the string are digits and isalpha() returns "True" if all characters in the string are alphabetic:

>>> d = {'number' : '1', 'name' : 'A'}
>>> d['number'].isdigit()
True
>>> d['number'].isalpha()
False
>>> d['name'].isdigit()
False
>>> d['name'].isalpha()
True

Upvotes: 1

umbreon29
umbreon29

Reputation: 233

Use the re module

 import re
 if re.match(r"\d+","12"): print('It is a number')

Upvotes: 1

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