CODEWITHSUNDEEP
pythonunicodeutf-8
b00r00x0
b00r00x0

Reputation: 953

TypeError: name() argument 1 must be a unicode character, not str

Hi I am trying to use unicodedata in python 3.7 on Linux but unfortunately it fails. Any help is highly appreciated.

I was looking on the net for the same issue but I couldn't find any hint which points me on the right direction.

My problem: I make use of unicodedata.name(string) and there I get an error TypeError: name() argument 1 must be a unicode character, not str.

Mininal working example

#!/usr/bin/env python3

import re
import emoji
import unicodedata


def replace_emoji(document):
    emoji_all = emoji.EMOJI_ALIAS_UNICODE.items()
    emoji_items = []

    emoji_pattern = re.compile(u'|'.join(
        re.escape(u[1]) for u in emoji_all), flags=re.UNICODE)
    emoji_items = re.findall(emoji_pattern, document)

    for item in emoji_items:
        unicodes = []
        unicode_values = []

        for char in range(len(item)):
            if not len(item) > 1:
                unicodes.append(r'{:x}'.format(ord(item[char])).upper())

            unicode_values.append([hex(ord(x)) for x in item[char]][0])

        char_length = len(unicode_values)

        chars = [chr(int(u, 16)) for u in unicode_values]

        if char_length == 2:
            print(chars)

            value = u'\\U{:x}\\U{:x}'.format(
                ord(chars[0]), ord(chars[1])).upper()

            unicodedata.name(value)

    return document

My test run

print(replace_emoji(u'🇯🇵🇰🇰🇷🇷🇩🇪🇨🇨🇳🇺🇺🇸🇫🇫🇷🇷🇪🇸🇸🇮🇹🇹🇷🇺🇬🇬🇧'))

Upvotes: 0

Views: 4430

Answers (1)

Johan Schiff
Johan Schiff

Reputation: 691

I believe you can treat all emoji chars as normal characters in python 3.

Can't test the code atm, but I think this should do it.

import emoji
import unicodedata


def replace_emojis(document):
    emoji_chars = emoji.EMOJI_ALIAS_UNICODE.values()

    def _emoji(char):
        if char in emoji_chars:
            return unicodedata.name(char)

    return ''.join(_emoji(char) or char for char in document)

Upvotes: 2

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