Reputation: 1
I have 6 different strings that I have combined together in a certain order to achieve what I want.
for a, b, c, d, e, f in zip(titles, artists, countrys, companys, values, years):
print(a, b, c, d, e, f)
I used a zip function to print each element of each string one by one.
I just need to add a hyphen between each element.
So for example one line of my output looks like this:
Empire Burlesque Bob Dylan USA Columbia 10.9 1985
But I need this:
Empire Burlesque - Bob Dylan - USA - Columbia - 10.9 - 1985
The hyphens separate each element of the 6 strings.
I was thinking whitespace replace but that would replace too much.
Any help is appreciated ! Thank you !
Upvotes: 0
Views: 504
Reputation: 1884
The print-function can do that when you supply the keyword argument sep
:
for a, b, c, d, e, f in zip(titles, artists, countrys, companys, values, years):
print(a, b, c, d, e, f, sep=" - ")
Or as an easier way for dealing with large collections: Note that your arguments should be strings then.
for description in zip(titles, artists, countrys, companys, values, years):
print(" - ".join(description))
If it's not all string, print
can handle different types and you could unpack your description:
for description in zip(titles, artists, countrys, companys, values, years):
print(*description, sep=" - ")
Approach that allows for formatting:
for description in zip(titles, artists, countrys, companys, values, years):
print("{} by {} from {} produced by {} going for {}$ (Year {})".format(*description))
Upvotes: 2