CODEWITHSUNDEEP
pythonpython-re
programminglearner
programminglearner

Reputation: 542

Python Get Text in Quotes After Pattern

I want to get the text in quotations after the occurrence of the pattern "name".

A sample string is: info = "name: joe", "name: jerry", "name: kate"

Here is what I'm doing:

import re

string = 'info = "name: joe", "name: jerry", "name: kate"'
array = re.findall(r'"(.*?)"', string)
for x in array:
       x = x.replace(" ","") #remove spaces because there might be space before colon occasionally 
       print(x.split("name:")[1])

The output prints:

joe
jerry
kate

I am just wondering if there is any easier way to do this and return the same output than what I did.

Upvotes: 0

Views: 108

Answers (2)

Mustafa Aydın
Mustafa Aydın

Reputation: 18306

You can embed the name: pattern in the regex, account for the occasional space before the colon via \s* and also match one or more spaces after colon and the actual name (where you are splitting from):

re.findall(r'"name\s*:\s+(.*?)"', string)
# ['joe', 'jerry', 'kate']

Upvotes: 1

Georgina Skibinski
Georgina Skibinski

Reputation: 13387

Try:

res=list(re.findall(r'\"name: ([^\"]+)"', string))

print(res)

2 important things - you extract only a group, hence the square brackets, and you define a name as set of one or more characters, that aren't double quotes ", since regex is on default greedy (i.e. matches the longest match only).

Outputs:

['joe', 'jerry', 'kate']

Upvotes: 1

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