CODEWITHSUNDEEP
java
Default
Default

Reputation: 794

Check if valid right angle from sides a,b ,c. BUT you can not use loops, conditionals, arrays or more advanced features

I have integers a, b and c.

Valid right angle means all the sides are positive integers, and they make a valid right angle triangle.

I'll then have to output the result (easy).

Full disclaimer: This is the course and assignment that I'm trying to finish

My attempt (Java):

// int a, b, c = 3, 4, 5;
// how do I even start checking if I'm not allowed to use "if / else"
// therefore not shown in code

int aSquare = a * a;
int bSquare = b * b;
int cSquare = c * c;
// *Im hoping they dont flag this as a conditional
System.out.println(
        (aSquare == (bSquare + cSquare) || bSquare == (cSquare + aSquare)
                || cSquare == (aSquare + bSquare))
);

Upvotes: 3

Views: 366

Answers (2)

Amir MB
Amir MB

Reputation: 3418

Based on the nature of the question, it is more meaningful to use assert in case if the user inputted a negative number:

 assert a > 0 && b > 0 && c > 0: "Sides can not be negative";

Also, you can use bitwise operators to extract sign of an integer:

// sign is 1 if i is zero, 0 if it is negative, 2 if it is positive 
int sign = 1 + (i >> 31) - (-i >> 31);

Upvotes: 0

Unmitigated
Unmitigated

Reputation: 89224

The smallest side is the minimum of a, b, and c; the largest side is the maximum of a, b, and c; and the other side is the sum of a, b, and c subtract the smallest side and the largest side. Then, all we need to do is check if the smallest side is larger than 0 and the square of the smallest side plus the square of the middle side is equal to the square of the largest side.

final int smallest = Math.min(a, Math.min(b, c));
final int largest = Math.max(a, Math.max(b, c));
final int middle = a + b + c - smallest - largest;
System.out.println(smallest > 0 && smallest * smallest + middle * middle == largest * largest);

Upvotes: 4

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